Do you have a picture of the whole question?
Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
-100/3,0
Step-by-step explanation:
substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
if that makes sense Hope this helps pls brainliest have a nice day :>
Answer:
<u>Has the form y = kx</u>
( y = 0.11x)
(y = 0.04x)
<u>Can be put into form y = kx</u>
(z/x = 9)
<u>Other</u>
(5 = xy)
( x = y/2)
Step-by-step explanation:
<u>y = kx</u>
( y = 0.11x)
(y = 0.04x)
<u>kx = y</u>
(z/x = 9)
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( x = y/2 )
( x - 5 = y)
(5 = xy)
(0,0)(1,3) = (3 - 0) / (1 - 0) = 3
slope = 3
equation for this line is y = 3x...and since u have (0,0) as a point on this line, ur y int is (0,0)
g(x) = 7x + 2...slope here is 7 and y int is (0,2)
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The slope of f(x) = 3. I found this using the slope formula (y2 - y1) / (x2 - x1).
The slope of g(x) = 7. Because in y = mx + b form, the slope is in the m position.
g(x) has a steeper slope.
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f(x) has a y int of (0,0)...the line cuts thru the origin.
g(x) has a y int of (0,2)...because in y = mx + b form, the y int will be in the b position.
So, g(x) has a greater y int.
