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Sophie [7]
3 years ago
8

How many moles are there in 135g of aluminum ?

Chemistry
1 answer:
dem82 [27]3 years ago
6 0

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Aluminium, or 26.981538 grams.

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const2013 [10]

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all I have to say is yea 1 like he said

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2 years ago
How many neutrons are in an atom of molybdenum-96 (Mo-96)
ziro4ka [17]
54 is your answer to this question
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What is the molas mass of lithium oxide li2o
gladu [14]
The molar mass of lithium oxide is 
29.88 g/mol
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What is the equilibrium membrane potential due to na ions if the extracellular concentration of na ions is 142 mm and the intrac
Ganezh [65]

The equilibrium membrane potential is 41.9 mV.

To calculate the membrane potential, we use the <em>Nernst Equation</em>:

<em>V</em>_Na = (<em>RT</em>)/(<em>zF</em>) ln{[Na]_o/[Na]_ i}

where

• <em>V</em>_Na = the equilibrium membrane potential due to the sodium ions

• <em>R</em> = the universal gas constant [8.314 J·K^(-1)mol^(-1)]

• <em>T</em> = the Kelvin temperature

• <em>z</em> = the charge on the ion (+1)

• <em>F </em>= the Faraday constant [96 485  C·mol^(-1) = 96 485 J·V^(-1)mol^(-1)]

• [Na]_o = the concentration of Na^(+) outside the cell

• [Na]_i = the concentration of Na^(+) inside the cell

∴ <em>V</em>_Na =

[8.314 J·K^(-1)mol^(-1) × 293.15 K]/[1 × 96 485 J·V^(-1)mol^(-1)] ln(142 mM/27 mM) = 0.025 26 V × ln5.26 = 1.66× 25.26 mV = 41.9 mV

4 0
3 years ago
What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?​
allochka39001 [22]

Answer:

1^{f} =187.7 \frac{J}{kg}

Explanation:

SO in order to calculate the specific latent heat of fusion, you need to remember the formula:

1^{f} =\frac{Q}{m}

Where 1^{f} representes the specific latent heart of fusion.

Q represents the heat energy added, usually represented in kJ

m represents the mass of the object, in kg.

Now that we have our formula we just have to put our values into the formula:

1^{f} =\frac{Q}{m}

1^{f} =\frac{863kJ}{4.6kg}

1^{f} =187.7 \frac{J}{kg}

SO our answer would be 1^{f} =187.7 \frac{J}{kg}

7 0
3 years ago
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