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Zigmanuir [339]
3 years ago
6

As the temperature of a gas is increased, the

Chemistry
1 answer:
Romashka [77]3 years ago
6 0

Answer:

B- Increase

Explanation:

In the event that the temperature is increased, the normal speed and dynamic energy of the gas atoms increment. In the event that the volume is held steady, the sped up the gas particles brings about more incessant and more powerful crashes with the dividers of the compartment, hence expanding the pressing factor

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Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.
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Give examples which indicate that nylon fibres are very strong.​
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2 years ago
What is the molarity of the solution resulting from the dissolution of 239 g glucose (C6H12O6) in 250
kifflom [539]

Answer:

Molarity =5.32 M

Explanation:

Given data:

Mass of glucose = 239 g

Volume = 250 mL (250 /1000 = 0.25 L)

Molarity = ?

Solution;

Formula:

Molarity = number of moles / volume in litter

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Number of moles = mass/ molar mass

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Molarity:

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6 0
3 years ago
PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

3 0
3 years ago
Read 2 more answers
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