The new speed of the glider is 42.2 m/s.
The new speed of the glider can be calculated using the principle of the law of conservation of energy.
Note: Total energy of the glider before the dive = Total energy of the glider after the dive.
<h3> Formula:</h3>
- mv²/2+mgh = mV²/2 +mgH................ Equation 1
Simplifying the equation above,
make V the subject of the equation.
- V = √[(v²/2)+gh]-gH]............... Equation 2
<h3>Where:</h3>
- V = New speed of the glider
- v = initial speed of the glider
- h = initial height of the glider
- H = New height of the glider
- g = acceleration due to gravity.
From the question,
<h3>Given:</h3>
- v = 40 m/s
- h = 300 meters
- H = 200 meters
- g = 9.8 m/s²
Substitute these values into equation 2.
- V = √[(40²/2)+(9.8×300)-(9.8×200)]
- V = √(800+2940-1960)
- V = √1780
- V = 42.2 m/s.
Hence, The new speed of the glider is 42.2 m/s.
Learn more about speed here: brainly.com/question/4931057
Answer:
1.25Hz
Explanation:
For waves on a string, the second harmonic is obtained from;
2fo = 1/l √T/M
Where;
l = length of the string
M= mass in kilograms
T = tension in the string
2fo = 1/2√5/0.8
2f0 = 1.25Hz
Answer:
find the masses of one is three times the mass of the other.
