Question

In the reaction between CO and Fe3O4, the theoretical yield in an experiment is calculated to be 47.2 g Fe. When a chemistry student carries out the experiment, the actual yield is 29.9 g Fe. Calculate the percentage yield. % Please show all work.
a. .633%

b 157%

c 63.3%

d .157%

Answer 1

Answer:

c 63.3%

Explanation:

Hello,

In this case, the percent yield is a measure of how effective was carried the reaction out and it is mathematically defined as:

$Y=\frac{m^{actual}}{m^{theoretical}} *100\%$

Now, for the given actual and theoretical yields we obtain:

$Y=\frac{29.9g}{47.2g} *100\%\\\\Y=63.3\%$

Thus, the answer is c 63.3% .

Best regards.

Answer 2

Answer:

C. 63.3%

Explanation:

Theoretical yield = 47.2g

Actual yield = 29.9g

Percentage yield = ?

The percentage yield of a compound after chemical synthesis is the ratio of the actual yield to the theoretical yield multiplied by 100.

Percentage yield = (actual yield / theoretical yield) × 100

Percentage yield = (29.9 / 47.2) × 100

Percentage yield = 0.6334 × 100

Percentage yield = 63.34%

The percentage yield of Fe is 63.34%