Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
Sorry I came a lil late,
The answer to your question is, 2.
Hope this helps! :)
Usually you would call this a saturated solution. I hope this helps.
Answer:
Ammonia, urea, uric acid
Explanation:
The given compounds are:-
Urea which has a molecular formula of
and has 2 atoms of nitrogen per molecule.
Ammonia which has a molecular formula of
and has 1 atom of nitrogen per molecule.
Uric acid which has a molecular formula of
and has 4 atoms of nitrogen per molecule.
Thus,
The order from least to most nitrogen is:-
Ammonia, urea, uric acid