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Effectus [21]
3 years ago
13

A weak base is titrated with a hydrochloric acid solution. What is the pH at the equivalence point?A) equal to pKaB) equal to 7C

) equal to pKbD) greater than 7E) less than 7
Chemistry
1 answer:
zvonat [6]3 years ago
4 0

Answer:

E) less than 7

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

pH scale generally runs from 1 to 14 where pH = 7 represents neutral medium, pH < 7 represents acidic medium and pH > 7 represents basic medium.

Strong acids dissociate completely and when they react with base they form a salt of weak base and strong acid.

For example, BOH is a weak base and HCl is the hydrochloric acid.

So,

BOH+HCl\rightarrow BCl+H_2O

<u>Thus, the salt is of weak base and strong acid which corresponds to pH less than 7.</u>

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Answer:

Oxygen.

Explanation:

They take in oxygen from the air. This is the process of respiration.

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Socratic an example of an atom that has no charge is one that has
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An example of an atom that has no charge is one that has a. 2 protons, 2 electrons, and 1 neutron.

To be neutral an atom must have the <em>same number</em> of protons (+) and electrons (-).

Only then will the <em>charges cancel</em> and give a neutral atom.


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3 years ago
A balloon is filled with 2.5 L of helium at 1 atm of pressure. If the pressure
ch4aika [34]

Answer:

5 L

Explanation:

Given data

  • Initial pressure (P₁): 1 atm
  • Initial volume (V₁): 2.5 L
  • Final pressure (P₂): 0.50 atm
  • Final volume (V₂): ?

For a gas, there is an inverse relationship between the pressure and the volume. Mathematically, for an ideal gas that undergoes an isothermic change, this is expressed through Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{1atm \times 2.5L}{0.50atm}= 5 L

8 0
3 years ago
What happens to an acid when it dissolves in water?
shusha [124]
The concentration of the acid decreases
5 0
3 years ago
Read 2 more answers
What is the ph of a solution that contains 1.0 l of 0.10 m ch3cooh and 0.080 m nach3coo after 0.03 moles of naoh added?
zimovet [89]

Answer: pH = 4.996

Explanation:

No of moles = molarity x volume

:• no of moles of CH3COOH = 0.1M x 0.1L

n(CH3COOH) = 0.1mol

Since 0.03mole of NaOH is added, then 0.03 mole of CH3COOH will be converted to the conjugate.

Therefore, Moles of CH3COOH becomes,

0.1 - 0.03 = 0.07 mol

Subsequently, the moles of CH3COONa increases and becomes,

0.08 + 0.03 = 0.11 mol

Using the Hendersom-Hasselbach equation,

pH = pKa + log [Moles of conjugate÷ moles of Ch3COOH]

From literature, pKa of Ch3COOH is 4.8

Thus,

pH = 4.8 + log [0.11/0.07]

pH = 4.8 + 0.1963

pH = 4.996

4 0
3 years ago
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