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Effectus [21]
4 years ago
13

A weak base is titrated with a hydrochloric acid solution. What is the pH at the equivalence point?A) equal to pKaB) equal to 7C

) equal to pKbD) greater than 7E) less than 7
Chemistry
1 answer:
zvonat [6]4 years ago
4 0

Answer:

E) less than 7

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

pH scale generally runs from 1 to 14 where pH = 7 represents neutral medium, pH < 7 represents acidic medium and pH > 7 represents basic medium.

Strong acids dissociate completely and when they react with base they form a salt of weak base and strong acid.

For example, BOH is a weak base and HCl is the hydrochloric acid.

So,

BOH+HCl\rightarrow BCl+H_2O

<u>Thus, the salt is of weak base and strong acid which corresponds to pH less than 7.</u>

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Explain intermolecular forces cause water molecules to stick to a material like a glass pitcher​
natulia [17]

Answer:

Cohesive forces cause the water molecules to stick together with a lot of elasticity, allowing the water to function very much like a rubber into a material like a glass pitcher.

6 0
3 years ago
Compare the electronegativity of H and O in the polar covalent bonds of a water
ExtremeBDS [4]

Answer:

The O atom will tend to attract the electrons.

Explanation:

The electronegativity of O (3.5) is much higher than H (2.1), which means it is more likely to attract electrons. The higher the electronegativity, the more attractive.

7 0
3 years ago
the scientific law of conservation of mass states that the total amount of mass in an isolated system remains constant. This mea
Verdich [7]
It describes how, when particles/mc/elements react, despite forming different substances the mass is neither created nor destroyed but only converted.
4 0
3 years ago
Read 2 more answers
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
4 years ago
Read 2 more answers
15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams
sveticcg [70]

Answer:

\boxed {\tt A. \ d=0.85 \ g/mL}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

m= 12.7 \ g\\v= 15 \ mL

Substitute the values into the formula.

d=\frac{12.7 \ g}{ 15 mL}

Divide.

d=0.846666667 \ g/mL

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

d \approx 0.85 \ g/mL

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

4 0
3 years ago
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