An ideal gas in a 1.25-gallon container is at a temperature of 125 degrees Celsius and pressure of 2.5 atmospheres. If the gas i s oxygen(formula:O2 molecular weight = 32 grams per mole), what is the mass of gas in the container in units of grams?
1 answer:
You will need the equation PV = nRT P = Pressure in kPa V = Volume in L n = moles R = 8.314 (constant) T = Temperature in Kelvin First convert 2.5 atm into kPa: 2.5 X 101.3 = 253.25 kPa Convert 125 Celsius into Kelvin: 125 + 273 = 398 K Convert Gallons to Litres: 1.25 X 3.79 = 4.74 L Plug your values into the equation to solve for n: (253.25)(4.74) = n(8.314)(398) n = (253.25)(4.74)/(8.314)(398) n = 0.362 moles Now use M = m/n to solve for the mass of O2 M = Molar Mass M = mass n= moles 32 = m/(0.362) m = (32)(0.362) m = 11.58g
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In this case, according to the given information, it turns out possible for us to calculate both moles and grams of lanthanum by using the Avogadro's number as a relationship of atoms to moles and its atomic mass as a relationship to moles to grams to obtain the following:
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