Answer:
c) Calculate the magnitude of the forces acting on the middle carriage during acceleration.
This is the answer of this question ok.
To solve this problem we will proceed to convert the Intensity Units given to a normal system, that is, to standardize their value. Later we will use the value of the electric field according to the RMS electric field, to find it.
Finally the magnetic field would be given based on the previously found electric field, depending on the speed of light:
The value of the intensity is:

The maximum value of the electric field is,


Where,
I = Intensity,
= Permeability constant
c = Speed of light
Replacing,


The maximum value of the magnetic field is,



Therefore the maximum magnetic field is 
Answer:

Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,

v = 2v

..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,


So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
Answer:
232 J/K
Explanation:
The amount of heat gained by the air = the amount of heat lost by the tea.
q_air = -q_tea
q = -mCΔT
q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)
q = 68,000 J
The change in entropy is:
dS = dQ/T
Since the room temperature is constant (isothermal):
ΔS = ΔQ/T
Plug in values (remember to use absolute temperature):
ΔS = (68,000 J) / (293 K)
ΔS = 232 J/K
I DONT know FiGURE it out YOURSELF