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alexandr402 [8]

2 years ago

14

Se lanza un cuerpo de 25 kg sobre un plano horizontal, con una velocidad de 20 m/s. Si el coeficiente de rozamiento es de 0,4 ca

lcula el valor de la fuerza de rozamiento y el espacio que recorrerá el cuerpo hasta pararse

1 answer:

Alex Ar [27]2 years ago

8 0

Answer:

1. 98 N

2. 51.0 m

Explanation:

masa 25 kg

velocidad 20 m/s

coeficiente de rozamiento .4

<u>Fuerza de rozamiento:</u>

mu * N, where mu = coeficiente de rozamiento, N = fuerza normal

Calcula N:

F = ma = 25 * -9.8 = -245 N

F rozamiento = mu * N = .4 * -245 = -98 N

<u>Espacio que recorrerá:</u>

F rozamiento = ma

-98 = 25a

a = -3.92 de-aceleración de la fuerza

vf = 0 m/s

vf = at + vi

0 = -3.92t + 20

t = 5.10 seg

x = 1/2 at^2 + vi*t

= 1/2 * -3.92 * 5.10^2 + 20*5.10

= 51.0 m

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