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vlabodo [156]
3 years ago
11

For a particular RLC series circuit, the capacitive reactance is 7.95 Ω , 7.95 Ω, the inductive reactance is 47.7 Ω , 47.7 Ω, an

d the maximum voltage across the 69.5 Ω 69.5 Ω resistor is 28.5 V . 28.5 V. What is the maximum voltage across the circuit?
Physics
1 answer:
I am Lyosha [343]3 years ago
7 0

Answer:

51.3165 V

Explanation:

The maximum voltage across the circuit is given as,

V' = IXc + IXl + Vr .................. Equation 1

Where V' = The maximum voltage across the circuit, I = current, Xc = capacitive reactance, Xl = inductive reactance, Vr = voltage cross the resistor.

From Ohm's Law,

V = IR........... Equation 2

I = V/R........... Equation 3

Given: V = 28.5 V, R = 69.5 Ω

Substitute into equation 3

I = 28.5/69.5

I = 0.41 A.

Also Given: Xc = 7.95 Ω, Xi = 47.7 Ω, Vr = 28.5 V.

Substitute into equation 1

V' = 7.95(0.41) + 47.7(0.41) + 28.5

V' = 3.2595+19.557+28.5

V' = 51.3165 V

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3 years ago
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
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Answer:

g=13.42\frac{m}{s^2}

Explanation:

1) Notation and info given

\rho_{center}=13000 \frac{kg}{m^3} represent the density at the center of the planet

\rho_{surface}=2100 \frac{kg}{m^3} represent the densisty at the surface of the planet

r represent the radius

r_{earth}=6.371x10^{6}m represent the radius of the Earth

2) Solution to the problem

So we can use a model to describe the density as function of  the radius

r=0, \rho(0)=\rho_{center}=13000 \frac{kg}{m^3}

r=6.371x10^{6}m, \rho(6.371x10^{6}m)=\rho_{surface}=2100 \frac{kg}{m^3}

So we can create a linear model in the for y=b+mx, where the intercept b=\rho_{center}=13000 \frac{kg}{m^3} and the slope would be given by m=\frac{y_2-y_1}{x_2-x_1}=\frac{\rho_{surface}-\rho_{center}}{r_{earth}-0}

So then our linear model would be

\rho (r)=\rho_{center}+\frac{\rho_{surface}-\rho_{center}}{r_{earth}}r

Since the goal for the problem is find the gravitational acceleration we need to begin finding the total mass of the planet, and for this we can use a finite element and spherical coordinates. The volume for the differential element would be dV=r^2 sin\theta d\phi d\theta dr.

And the total mass would be given by the following integral

M=\int \rho (r) dV

Replacing dV we have the following result:

M=\int_{0}^{2\pi}d\phi \int_{0}^{\pi}sin\theta d\theta \int_{0}^{r_{earth}}(r^2 \rho_{center}+\frac{\rho_{surface}-\rho_{center}}{r_{earth}}r)

We can solve the integrals one by one and the final result would be the following

M=4\pi(\frac{r^3_{earth}\rho_{center}}{3}+\frac{r^4_{earth}}{4} \frac{\rho_{surface}-\rho_{center}}{r_{earth}})

Simplyfind this last expression we have:

M=\frac{4\pi\rho_{center}r^3_{earth}}{3}+\pi r^3_{earth}(\rho_{surface}-\rho_{center})

M=\pi r^3_{earth}(\frac{4}{3}\rho_{center}+\rho_{surface}-\rho_{center})

M=\pi r^3_{earth}[\rho_{surface}+\frac{1}{3}\rho_{center}]

And replacing the values we got:

M=\pi (6.371x10^{6}m)^2(\frac{1}{3}13000 \frac{kg}{m^3}+2100 \frac{kg}{m^3})=8.204x10^{24}kg

And now that for any shape the gravitational acceleration is given by:

g=\frac{MG}{r^2_{earth}}=\frac{(6.67408x10^{-11}\frac{m^3}{kgs^2})*8.204x10^{24}kg}{(6371000m)^2}=13.48\frac{m}{s^2}

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The velocity of the girl is  -4.8 m/s.

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v = -4.8 m/s

Note that the negative sign shows that the velocity of the girl is in opposite direction that that of the girl.

Learn more about momentum: brainly.com/question/904448

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