Answer:
A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.
Explanation:
A buffer is a solution which resists changes to its pH when a small amount of acid or base is added to it.
Buffers consist of a weak acid (HA) and its conjugate base (A–) or a weak base and its conjugate acid. Weak acids and bases do not completely dissociate in water, and instead exist in solution as an equilibrium of dissociated and undissociated species. When a small quantity of a strong acid is added to a buffer solution, the conjugate base, A-, reacts with the hydrogen ions from the added acid to form the weak acid and a salt thereby removing the extra hydrogen ions from the solution and keeping the pH of the solution fairly constant. On the other hand, if a small quantity of a strong base is added to the buffer solution, the weak acid dissociates further to release hydrogen ions which then react with the hydroxide ions of the added base to form water and the conjugate base.
For example, if a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, the following reaction is obtained:
KH₂PO₄ + H+ ----> K+ + H₃PO₄
Therefore, [H₃PO₄] will increase, [KH₂PO₄] will decrease, and pH will slightly decrease.:
Well, the sun is in space, right? It has to be able to transfer heat through space, or how would it get to us? Radiation helps transfer heat.
To get the molarity, you divide the mass in moles over the amount in liters. To convert the grams to moles, divide the amount of grams by the molar mass. In this case, I believe sucrose has a molar mass of 342.297. Once you divide 171/342.297 you should get .4996. Now divide that by the .750 to get a final answer of .6660. Check to make sure you don't have to follow the significant figure rules.
You can reduce the charges and subscripts so it is PbS2
Answer:
Molecules in order of decreasing rate of effusion:
Explanation:
Mass of 
gas= 
Mass of 
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Mass of 
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Mass of 
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According Graham's law:
'The rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas'.The equation given by this law follows the equation:
So, higher the molecular mass of the gas lower will be the effusion rate and vice versa.
Increasing order of molecular masses of the given gases:
Decreasing order of effusion rate respective to gases:
Molecules in order of decreasing rate of effusion:
