Answer:
53.3 %.
Explanation: C2H4O2. = 2 * 12.011 + 4 * 1.008 + 2 * 15.999. = 60.052.
Answer:
Explanation:
Mass ( m ) = 52 kg
Acceleration ( a ) = 5 m / s²
Force ( F ) = ?
According to Newton's second law of motion ,
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Answer:
<em>This type of error affects overall accuracy but does not necessarily affect precision.</em> - Systematic error
<em>This type of error affects precision but does not necessarily affect overall accuracy.</em> - Random error
<em>This type of error occurs if you use a buret that was calibrated incorrectly when it was made.</em> - Systematic error
<em>You can minimize this type of error by taking repeated measurements.</em> - Random error
Explanation:
<em>Systematic errors are errors that are attributable to instrument being used during measurement or consistent incorrect measurement during a research</em>. They are consistently and repeatedly committed during measurements and therefore affect the overall accuracy of measurements. A person committing systematic error can have precise repeated measurement but will be far from being accurate.
R<em>andom errors on the other hand has no pattern and are usually unavoidable because they cannot be predicted.</em> When sufficient replicate measurements are made, such errors are reduced to the barest minimum and usually do not affect the overall accuracy of measurements.
Chlorine + aluminium bromide --> aluminium chloride + bromine
Chlorine replaces bromide in AlBr3
3Cl2 + 2AlBr3 ---> 2AlCl3 + 3Br2
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First step is to calculate the mass of Ag in each compound separately:
From the periodic table:
molar mass of Ag is 107.87 gm
molar mass of Cl is 35.45 gm
molar mass of Br is 79.9 gm
For AgCl, mass % of Ag = [107.87/143.32] x 100 = 75.26%
For AgBr, mass % of Ag = [107.87/187.77] x 100 = 57.45 %
Second step is to calculate the mass % of each compound in the mixture:
Assume mass % of AgCl is y and that of AgBr is (1-y) as the total percentage is 100% or 1
0.6094 = 0.7526 y + 0.5745 (1-y)
y = 0.8716
This means that the mixture is almost 87% AgCl and 13% AgBr
The mass % of chlorine and bromine together is (100%-60.94%) which is 39.06%
mass % of chlorine = (1-0.6094)(0.8716) x 100 = 34.044%
mass % of bromine = 39.04 - 34.044 = 5.056%
