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EleoNora [17]
2 years ago
12

Số oxi hóa của các nguyên tố: Fe(OH)2; Fe(OH)3; FexOy; Zn(OH)2 là gì

Chemistry
1 answer:
BARSIC [14]2 years ago
7 0

Answer:

esfsef

Explanation:

esfsefseF

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What is the mass of a liquid that has a volume of 50.0ml and a density of 2.40g/ml?
Iteru [2.4K]

Answer:

120g Using Density Equation.

Explanation:

Density =mass/volume

We need to the solve for the mass.

Mass=Density * Volume

Mass= 2.40 g/ml * 50.0 ml = 120g

5 0
3 years ago
Una muestra de oxígeno ocupa 4.2 litros a 760 mm de hg . ¿ cual será el volumen del oxigeno a 415 mm de hg , si la temperatura p
ddd [48]

Teniendo en cuenta la ley de Boyle, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Al aumentar el volumen, las partículas (átomos o moléculas) del gas tardan más en llegar a las paredes del recipiente y por lo tanto chocan menos veces por unidad de tiempo contra ellas. Esto significa que la presión será menor porque ésta representa la frecuencia de choques del gas contra las paredes.

De esta manera se relaciona la presión y el volumen, determinando la ley de Boyle que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:

P×V=k

Teniendo un estado inicial 1 y final 2, se cumple:

P₁×V₁= P₂×V₂

En este caso, se sabe que:

  • P₁= 760 mmHg
  • V₁= 4.2 L
  • P₂= 415 mmHg
  • V₂= ?

Reemplazando en la expresión matemática para la Ley de Boyle:

760 mmHg× 4.2 L= 415 mmHg× V₂

Resolviendo:

(760 mmHg× 4.2 L)÷ 415 mmHg= V₂

<u><em>7,69 L= V₂</em></u>

Finalmente, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

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5 0
2 years ago
Easy questions ha chemistry
joja [24]

Answer:

B

A

D

Explanation:

3 0
3 years ago
Read 2 more answers
Oxygen freezes at -219°c and boils at -183°c in which state is oxygen at -200°c​
vova2212 [387]

oxygen is in gaseous state at this temperature

4 0
2 years ago
A gas occupying a volume of 656.0 mL at a pressure of 0.884 atm is allowed to expand at constant temperature until its pressure
7nadin3 [17]

Answer:

1.14 × 10³ mL

Explanation:

Step 1: Given data

  • Initial volume of the gas (V₁): 656.0 mL
  • Initial pressure of the gas (P₁): 0.884 atm
  • Final volume of the gas (V₂): ?
  • Final pressure of the gas (P₂): 0.510 atm

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL

5 0
2 years ago
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