The correct unabbreviated electron configuration is as below
Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2
Strontium - 1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2
Carbon =1S2 2S2 2P2
<u><em> Explanation</em></u>
vanadium is in atomic number 23 in the periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2
Strontium is in atomic number 38 in periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4s2
Carbon is in atomic number 6 in periodic table therefore its electron configuration is 1s2 2s2 2p2
Answer:
Las moléculas de los reactivos tienen que chocar entre sí. Estos choques deben de producirse con energía suficiente de forma que se puedan romper y formar enlaces químicos. En el choque debe haber una orientación adecuada para que los enlaces que se tienen que romper y formar estén a una distancia y posición viable.
<span>1080.9523809 should be the answer</span>
Wait what you answered your own question
<span>This problem is not about chemistry it is about math. the half-life of a certain thing is the time that it needs to decay 50% of what it had before. so if there is 4g, after 1 half there will be only 2g. so to become 1g it is passed 2 half-lives. 4,0g, 2,0g, 1,0g so it is the time divided by 2( numbers of half-lives). So the half-life of Francium 210 is 2,6 min.</span>
