Answer:
Question A: 17.92m/s
Question B: 0.6 seconds
Explanation:
Question A:
Initial velocity(u)=24m/s
Height(h)=13m
acceleration due to gravity(g)=9.8m/s^2
Final velocity=v
v^2=u^2-2xgxh
v^2=24^2-2x9.8x13
v^2=24x24-2x9.8x13
v^2=576-254.8
v^2=321.2
Take them square root of both sides
v=√(321.2)
v=17.92m/s
Question B:
velocity(v)=17.92m/s
Acceleration due to gravity(g)=9.8m/s^2
Initial velocity(u)=24m/s
Time=t
v=u-gxt
17.92=24-9.8xt
Collect like terms
9.8t=24-17.92
9.8t=6.08
Divide both sides by 9.8
9.8t/9.8=6.08/9.8
t=0.6 approximately
Answer:
4375 N, 7875 N
Explanation:
since the body is equilibrium
total upward force = total downward force
w weight of the bridge = FL + FR
when the car was introduced,
total downward force = total upward force
FL₁ + FR₁ = w + (m × acceleration due to gravity) with w = FL + FR
then FL₁ + FR₁ = FL + FR + Mcg
FL₁ + FR₁ - FL - FR = Mcg
ΔFL + ΔFR = 1250 × 9.8 = 12250 N
taken the left as the pivot point and using the principle of moment
ΔFR × 14 m = 12250 N × 5 m + (ΔFL × 0 m) since the left is the pivot point.
ΔFR = 61250 / 14 = 4375 N
but
ΔFL + ΔFR = 12250 N
ΔFL = 12250 - 4375 = 7875 N
Answer:banana
Explanation:
Because the amount of potassium is that
Answer: The formula of Newtons second law of motion is F=MA so therefore it would be written like this Force = Mass X Acceleration
F = 5 x 2
F = 10 N
