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3 years ago

Is loudness affected by change in frequency? Explain I will mark you the brainliest

Physics

1 answer:

zmey [24]3 years ago

4 0

Answer:

Explanation:

To increase or decrease loudness, you have to change the amplitude

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Suppose that on a hot (33.0°C) and sticky (80% humidity) afternoon in the spring, a tornado passes over the high school. If the

pickupchik [31]

Answer:

V₂ = 225 m^{3}

so no exact option is match with the calculated answer.

Explanation:

According to Boyle's Law, we have

P_1 V_1 = P_2 V_2 ----------- (1)

Data Given;

P_1 = 1.0 atm

V_1 = 180 m³

P_2 = 0.80 atm

V_2 = ?

Solving equation 1 for V₂,

$V_2= \frac{P_1 V_1}{P_1}$

Putting values,

$V_2 = \frac{1.0*180}{0.80}$

$V_2 = 225 m^{3}$

so no exact option is match with the calculated answer.

6 0

3 years ago

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If a substance or object has the ability to do work, then it has

LUCKY_DIMON [66]

Energy is the ability to do work.

7 0

3 years ago

What is the value of ΔVBA=VB−VA if the charge on the plates is 1.00 x 10-9 C, the area of the plates is 2.00 m2 and the distanc

Murljashka [212]

Answer:

The Value is $V_{AB} = 2.825V$

Explanation:

The explanation is shown on the first uploaded image

5 0

3 years ago

An object with mass 3.5 kg is attached to a spring with spring stiffness constant k = 270 N/m and is executing simple harmonic m

Elanso [62]

Answer:

Part a)

A = 0.066 m

Part b)

maximum speed = 0.58 m/s

Explanation:

As we know that angular frequency of spring block system is given as

$\omega = \sqrt{\frac{k}{m}}$

here we know

m = 3.5 kg

k = 270 N/m

now we have

$\omega = \sqrt{\frac{270}{3.5}}$

$\omega = 8.78 rad/s$

Part a)

Speed of SHM at distance x = 0.020 m from its equilibrium position is given as

$v = \omega \sqrt{A^2 - x^2}$

$0.55 = 8.78 \sqrt{A^2 - 0.020^2}$

$A = 0.066 m$

Part b)

Maximum speed of SHM at its mean position is given as

$v_{max} = A\omega$

$v_{max} = 0.066(8.78) = 0.58 m/s$

4 0

3 years ago

Which graph shows the relationship between temperature, X, and kinetic energy, Y?

strojnjashka [21]

Answer: see the graph attached (straight line, passing through the origin and positive slope).

Justification:

1) Kinetic energy and temperature are in direct proportion. That means:

i) Being kinetic energy y and temperature x: y α x

ii) That implies: y = kx,where k is the constant of proportionality.

iii) The graph is a line that passes through the origin and has positive slope k (k = y / x).

2) The proportional relationship between kinetic energy (KE) and temperature (T) is shown by the Boltzman law, which states:

Average KE = [3 / 2] KT, where K is Boltzman's constant, whose graph is of the form shown in the figure attached.

5 0

3 years ago

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