3 years ago

Is loudness affected by change in frequency? Explain I will mark you the brainliest

Physics

1 answer:

zmey [24]3 years ago

4 0

Answer:

Explanation:

To increase or decrease loudness, you have to change the amplitude

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1. As a person stands on earth they put a force on the ground and the ground puts a force on them.

Scorpion4ik [409]

Answer:

Explanation:

m b

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2 years ago

The melting point of potassium thiocyanate determined by a student in the laboratory turned out to be 174.5 oC. The accepted val

yaroslaw [1]

Answer:

0.75%

Explanation:

Measured value of melting point of potassium thiocyanate = 174.5 °C

Actual value of melting point of potassium thiocyanate = 173.2 °C

Error in the reading = |Experimental value - Theoretical value|

= |174.5 - 173.2|

= |1.3|

Percentage error = (Error / Theoretical value) × 100

= (1.3 / 173.2)×100

= 0.75 %

∴ Percentage error in the reading is 0.75%

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3 years ago

What body parts were scientists wanting to image that prompted the development of the CT scanner

zalisa [80]

Answer:

The head

Explanation:

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3 years ago

In the picture of the atom above, what subatomic particle does the letter A represent?

ra1l [238]

Answer:

Electron

Explanation:

In the picture, the letter A is pointing to an electron.

4 0

3 years ago

The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the

Airida [17]

Answer:

$\frac{I}{I_0}=113.68$

Explanation:

P = Acoustic power = 63 µW

r = Distance to the sound source = 210 m

Acoustic power

$P=IA\\\Rightarrow I=\frac{P}{A}\\\Rightarrow I=\frac{63\times 10^{-6}}{4\times \pi \times 210^2}$

Threshold intensity = $I_0=1\times 10^{-12}\ W/m^2$

Ratio

$\frac{I}{I_0}=\frac{\frac{63\times 10^{-6}}{4\times \pi \times 210^2}}{1\times 10^{-12}}\\\Rightarrow \frac{I}{I_0}=113.68$

Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68

6 0

3 years ago