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3 years ago

7

A light plastic cart and a heavy steel cart are both pushed with the same force for 1.0 s, starting from rest. After the force i

s removed, the momentum of the light plastic cart is ________ that of the heavy steel cart.

1 answer:

Sergeu [11.5K]3 years ago

3 0

Answer:

my friend give options .............

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What happens to the density when water is poured into a empty glass?

san4es73 [151]

-- The density of the glass alone doesn't change.

-- The density of the water alone doesn't change.

-- The density of (the entire glass + everything IN IT) increases,
because the part that used to be air (with very low density) is
changed to water (with much higher density than the air had).

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3 years ago

When Mary talks, she creates an intensity level of 60 dB at your location. Alice talks with the same volume, also giving 60 dB a

a_sh-v [17]

Answer:

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Explanation:

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3 years ago

Does volume affect potential energy

Andrej [43]

Answer:

No, the volume don't affect the potential energy.

Explanation:

The volume does not affect the potential energy, as this energy depends on the mass and elevation of the body relative to the reference point. This analysis can be easily seen in the equation expressing potential energy

$E_{p} =m*g*h\\where:\\m=mass[kg]\\g=gravity[m/^2]\\h=elevation[m]$

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4 years ago

How would you eliminate the unit in this conversion? 5 mil to m

m_a_m_a [10]

Answer:

https://youtu.be/9iulv2QvKwo

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3 years ago

A girl coasts down a hill on a sled, reaching level ground at the bottom with a speed of 7.1 m/s. The coefficient of kinetic fri

Lelu [443]

Answer:

114.19186 m

Explanation:

v = Velocity of girl at bottom = 7.1 m/s

$\mu$ = Coefficient of kinetic friction = 0.045

g = Acceleration due to gravity = 9.81 m/s²

d = Distance

N = Normal force = 783 N

The weight of the sled and girl is considered as the sum of the frictional force and weight

Hence we use the following equation where the kinetic energy and potential energy are conserved

$\frac{1}{2}mv^2=\mu Nd\\\Rightarrow \frac{1}{2}\frac{783}{9.81}\times 7.1^2=0.045\times 783\times d\\\Rightarrow d=\frac{1}{2}\times \frac{783\times 7.1^2}{9.81\times 0.045\times 783}\\\Rightarrow d=114.19186\ m$

The sled travels 114.19186 m on the level ground before coming to a rest

5 0

3 years ago