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2 years ago

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A light plastic cart and a heavy steel cart are both pushed with the same force for 1.0 s, starting from rest. After the force i

s removed, the momentum of the light plastic cart is ________ that of the heavy steel cart.

1 answer:

Sergeu [11.5K]2 years ago

3 0

Answer:

my friend give options .............

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driving down the highway , you find yourself behind a heavily loaded tomato truck. you follow close behind the truck keeping the

prohojiy [21]

Answer:

The tomato won't hit the car

Explanation:

According to the statement, the car moves at constant speed behind the truck fully loaded with tomatoes, and in the same direction. When a tomato falls from the top of the truck, it should not hit the car as the tomato falls due to the force of gravity, while horizontally has the same speed and in the same direction as the truck. So we assume that the tomato will fall to the road without touching the car.

Have a nice day!

4 0

3 years ago

Wave C has an amplitude of 1 and wave D has an amplitude of 3 as shown below. What will happen when the trough of wave C meets t

gtnhenbr [62]

They will interfere to create a crest with an amplitude of 2

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3 years ago

Read 2 more answers

In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is

meriva

The spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

<h3>What is double slit experiment?</h3>

The double-slit experiment serves as a proof in current physics that both light and matter may exhibit properties of classically defined waves and particles. It also illustrates the inherently probabilistic nature of quantum mechanical events. Thomas Young carried out the first experiment of this kind employing light in 1802, illustrating how light behaves like a wave. It was formerly believed that light was made up of either waves or particles. About a century later, with the advent of modern physics, it was discovered that light may in fact exhibit behaviour like that of both waves and particles. The identical behaviour of electrons was first shown by Davisson and Germer in 1927, and it was later extended to atoms and molecules.

The separation between the slits, d = 0.05mm = 5×10⁻⁵ m

The distance from the slits to a screen, D = 2.5 m

Let x is the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits,

λ = 600nm = 6× 10⁻⁷ m

We know that the bright fringe is given by :

y = nλD/d

So, the spacing between the first-order and second-order bright fringes is :

x = 2λD/d - λD/d

x = λD/d

x = 6 × 10⁻⁷ × 2.5/5 × 10⁻⁵

x = 0.03 m

or

x = 3 cm

So, the spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

to learn more about double slit experiment go to -

brainly.com/question/28108126

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8 0

1 year ago

Which type of ooze dominates in warm shallow ocean floors?<br>A. Calcareous<br>B. Silieous

gogolik [260]

Actually it's sediment

6 0

3 years ago

It would take almost 2 years for the fastest human-made spacecraft to travel from earth to europa. about how long would it take

worty [1.4K]

First, we need the distance of Europe and Wolf-359 from Earth.
- The distance of Europe from Earth is: $d_E = 6.28 \cdot 10^8 km$
- The distance of Wolf-359 from Earth is instead 7.795 light years. However, we need to convert this number into km. 1 light year is the distance covered by the light in 1 year. Keeping in mind that the speed of light is $c=3 \cdot 10^8 m/s$ , and that in 1 year there are
365 days x 24 hours x 60 minutes x 60 seconds = $3.154 \cdot 10^7 s/y$ , the distance between Wolf-359 and Earth is
$d_W = 7.995 ly\cdot3\cdot 10^8 m/s \cdot 3.154 \cdot 10^7 s=7.38 \cdot 10^{16}m=7.38 \cdot 10^{13}km$

Now we can calculate the time the spaceship needs to go to Wolf-359, by writing a simple proportion. In fact, we know that the spaceship takes 2 years to cover $d_E$ , so
$2 y:d_E = x:d_W$
from which we find $x$ , the time needed to reach Wolf-359:
$x= \frac{2 y\cdot d_W}{d_E}=2.35 \cdot 10^5 years$

4 0

3 years ago