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2 years ago

Four forces act on a hot-air balloon, as shown

Physics

1 answer:

dolphi86 [110]2 years ago

5 0

The magnitude of the resultant force on the balloon is 374.13 N.

The given forces from the image;

Upward force = 514 N
Downward force = 267 N
Eastward force = 678 N
Westward force = 397 N

The net vertical force on the balloon is calculated as follows;

$F_y = 514 \ N \ \ - \ \ 267 \ N\\\\F_y = 247 \ N$

The net horizontal force on the balloon is calculated as follows;

$F_x = 678 \ N \ - \ 397 \ N\\\\F_x = 281 \ N$

The magnitude of the resultant force on the balloon is calculated as follows;

$F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(247)^2 + (281)^2} \\\\F= 374.13 \ N$

Thus, the magnitude of the resultant force on the balloon is 374.13 N.

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To find the relative velocity of one electron with respect to the other, we must use the following formula:

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In this problem:

u = 0.2c

v = -0.2c (since the second electron is moving towards the first one, so in the opposite direction)

Substituting, we find:

$u'=\frac{0.2c+0.2c}{1+\frac{(0.2c)(0.2c)}{c^2}}=\frac{0.4c}{1+0.04}=0.38c$

2) In the reference frame of the laboratory: -0.2c and +0.2c

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3 years ago

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3 years ago

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3 years ago

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disa [49]

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3 years ago

A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec

Dennis_Churaev [7]

Answer:

Power of the string wave will be equal to 5.464 watt

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Frequency f = 8 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 8=50.24rad/sec$

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Power of wave propagation is equal to $P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt$

So power of the wave will be equal to 5.464 watt

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3 years ago