The perimeter of a triangle is the sum of its side lengths.
The perimeter of the triangle is: 
<u>The sides of the triangle are:</u>
Side 1 = (8d - 3) cm
Side 2 = (6d + 2) cm
Side 3 = (7f + 8) cm
The perimeter (P) is calculated as:
P = Side 1 + Side 2 + Side 3
So, we have:

Remove brackets

Collect like terms


Hence, the perimeter of the triangle is: 
Read more about perimeters at:
brainly.com/question/6465134
Answer:
x = - 80/17, or x = - 4 
Step-by-step explanation:
13x-11 +18×15+ 4x+1=180°
<=> (13x + 4x) + (18×15+ 1 - 11)=180°
<=> 17x + 260 =180
<=> 17x = 180 - 260
<=> 17x = - 80
<=> x = - 80/17
<=> x = - 4 
1 mi = 5280 ft
1 h = 3600 s
therefore:

Answer: 31.8 mi/h = 46.64 ft/s
Answer:
75
Step-by-step explanation:
That means she type 450/6 minutes. Take 450 and divide it by 6.
450/6 = 75
6. It is asking you to find the surface area for this one:
1 litre = 0.001 cubic meters
15.4 litres = 0.0154 cubic meters
The volume of the cylinder has to be 0.0154m^3.
V = (pi(r)^2)h
0.0154 = (pi(r)^2)(1)
r^2 = 0.0154/pi
r = 0.07m
Surface Area of Circles on Bottom:
A = pi(r)^2
A = pi(0.07)^2
A = 0.0154
0.0154*2 = 0.0308m^2
Surface Area of Walls:
This will be the circumference of the circle times the height, since the walls are just like a big rectangle.
C = 2pi(r)
C = 2pi(0.07)
C = 0.44m
0.44*1 = 0.44m^2
Finally, add the two surface areas:
0.44 + 0.0308 = 0.47m^2
You will need 0.47m^2 of sheet metal to make this cylinder.
7. Find the volume of everything and just the graphite, and subtract the graphite’s volume from everything to get just the wood. The volume of a cylinder is pi((r)^2)h.
Everything:
Watch out for units, since the diameter is in mm and the length is in cm.
r = 3.5mm or 0.35cm
V = pi((0.35)^2)(14)
V = 5.34cm^3
Graphite:
r = 0.5mm or 0.05cm
V = pi((0.05)^2)(14)
V = 0.11cm^3
5.34 - 0.11 = 5.23cm^3
8. For this problem, it wants your answer in cm^3. Find the volume of one bowl and multiply it by 250:
r = 3.5cm
V = pi((3.5)^2)(4)
V = 153.94cm^3
153.94*250 = 38484.51cm^3 of soup needed.
I sure hope that I didn’t confuse you too much with all of my math gibberish (sorry). Please let me know if there is anything else that I can help with. Have a nice day