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AysviL [449]
3 years ago
10

2.A 5 Ohm resistor is connected to a 9 Volt battery. How many Joules of thermal energy are produced in 7 minutes?

Physics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

Explanation:

2 )

power of an electric device = V² / R where V is volts and R is resistance

putting given data

power = 9²/ 5

= 16.2 J/s

energy produced in 7 minutes

= 16.2 x 7 x 60

= 6804J .

3 ) Power of an electrical device

= V² / R

= V X I where I  is current

= 4.5 x .5

= 2.25 W or J/s

4 )

energy used in 3 minutes with power of 2.25 W

= 2.25 x 3 x 60

= 405 J .

7 )

power of a electrical device

= V x I

IR x I  where R is resistance .

= I²R

putting given data

power = .005² x 50

= 1.25 x 10⁻³ W .

8 )

Energy used up by a 60 W bulb in 2.5 hours

= 60 x 2.5 x 60 x 60

= 5.4 x 10⁵ J .

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The induced magnetic field at radial distance 4.0 mm from the central axis of a circular parallel-plate capacitor is 1.8 ✕ 10−7
wel

Answer:

\frac{dE}{dt}=2.07*10^{13}\frac{V/m}{s}

Explanation:

According to Gauss's law, the electric flux through the circular plates is defined as the electric field multiplied by its area:

\Phi=EA=E(\pi R^2)(1)

The magnetic field around the varying electric field of the circular plates is given by:

B=\frac{\epsilon_0 \mu_o}{2\pi r}\frac{d\Phi}{dt}(2)

Replacing (1) in (2) and solving for \frac{dE}{dt}:

B=\frac{\epsilon_0 \mu_o\pi R^2}{2\pi r}\frac{dE}{dt}\\\frac{dE}{dt}=\frac{2rB}{\epsilon_0 \mu_o R^2}\\\frac{dE}{dt}=\frac{2(4*10^{-3}m)(1.8*10^{-7}T)}{(8.85*10^{-12}\frac{C^2}{N\cdot m^2})(4\pi *10{-7}\frac{Tm}{A})(2.5*10^{-3}m)^2}\\\\\frac{dE}{dt}=2.07*10^{13}\frac{V/m}{s}

3 0
3 years ago
What net external force is exerted on a 1100-kg artillery shell fired from a battleship if the shell is accelerated at 2.40×104
pickupchik [31]

Answer:

Force exerted, F = 2.64 × 10⁷ Newton

Explanation:

It is given that,

Mass of the artillery shell, m = 1100 kg

It is accelerated at, a=2.4\times 10^4\ m/s^2

We need to find the magnitude of force exerted on the ship by the artillery shell. It can be determined using Newton's second law of motion :

F = ma

F=1100\ kg\times 2.4\times 10^4\ m/s^2

F = 26400000 Newton

or

F = 2.64 × 10⁷ Newton

So, the force exerted on the ship by the artillery shell is 2.64 × 10⁷ Newton.

6 0
4 years ago
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A meter stick whose mass is 290 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a
katen-ka-za [31]

Answer

given,

mass of the stick = 290 grams = 0.29 Kg

Force on the stick on one side = F =  9 N

force acting perpendicular to stick.

magnitude of acceleration

rate of change of angular momentum is equal to Force

rate of change of angular momentum = 9 N

F = m a

a = \dfrac{F}{m}

a = \dfrac{9}{0.29}

a = 31.034 m/s²

Direction of motion will in the direction of force application or in the direction of change of velocity

5 0
4 years ago
An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m
ddd [48]

Answer:

Velocity of electron will be 1.325\times 10^6m/sec

Explanation:

We have given distance across the plate d = 2 mm =2\times 10^{-3}m

Potential difference V = 6 volt

We know that potential difference at any distance is given by

V = Ed , here V is potential difference, E is electric field and d  is distance

So E=\frac{V}{d}=\frac{6}{2\times 10^{-3}}=3000N/C

Charge on electron e=1.6\times 10^{-19}C

We know that expression of velocity is given by v=\sqrt{\frac{2qEd}{m_e}}, here q is charge on electron, E is electric field and d is distance

So v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 3000\times 3000}{9.11\times 10^{-31}}}=1.325\times 10^6m/sec

8 0
4 years ago
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Svet_ta [14]
Multiple transformations occur as a result of the chemical energy in the fuel is changed to several forms of energy.
6 0
3 years ago
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