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ch4aika [34]
3 years ago
6

What is the best name for this molecule? Explain your naming process.

Chemistry
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

for compound CH3 it is named methyl or methyl, for compound CH3 -CH2-Ch2 C ||| since it is an alkyne for the triple bond that is why it is a group of carbons called propyne, on the other hand the last equation where CH3-CH-C is expressed, I think you meant CH3-CH-CH2 || with which this last serious propene since the double bond is what makes it an alkene.

Explanation:

The compound CH3-CH-C was considered poorly written since a carbon can always bind four hydrogens, so if the molecule is CH3 it is because it has 3 available bonds to bind with the hydrogens and one with an R (radical) If the molecule is CH2, it is because it is linked to two radicals on each side and it only has two available bonds for hydrogens or because it has a double bond, on the other hand, in the case that it is CH or it has a triple bond or is attached to three other radicals / carbons and only one bond is available for bonding with hydrogen-

It is important to understand that if a carbon in an organic chemical sequence is only expressed as C, it is because its four unions are occupied and cannot bind to hydrogens, thus being the opposite case of methane, which is CH4 where ALL ITS UNIONS ARE WITH HYDROGENS SINCE IT IS NOT JOINED TO ANY RADICAL.

Organic chemistry is difficult, I hope the equations you wrote are well expressed, otherwise if you have doubts you can consult me.

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Yakvenalex [24]
Argument would make the most sense
3 0
3 years ago
49. How much precipitate would result if you have 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation
Gennadij [26K]

Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.

<h3>What is Solubility ?</h3>

the maximum quantity of a substance that will dissolve in a certain quantity of water at a specified temperature.

From the Solubility Graph of NaCl , we can see that the solubility of NaCl at 10 C is around 36.5gm/L.

If it is cooled down to saturation we will see the precipitate forming and that will be equal to the difference of solute present and the solubility.

As it is given that 50gm of solute is present

The precipitate will be 50- 36.5 gm, = 13.5 gm.

Therefore Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.

To know more about Solubility

brainly.com/question/8591226

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7 0
2 years ago
Diamond has a density of 3.52 g/ml. what is the volume in cubic centimeters of a diamond with a mass of 15.1 g? 4.3 cm3 4.29 cm3
Kamila [148]
Density of 3.52g/ml means for each milliliter of space there are 3.52 grams of diamond.

To set the stage:
\frac{3.52}{1}  =  \frac{15.1}{x}
Set the denominators equal:
\frac{3.52x}{x}  =  \frac{15.1}{x}
Remove the denominators:
3.52x = 15.1
Isolate x by dividing both sides by 3.52:
x = 4.289772 {cm}^{3}
6 0
3 years ago
Read 2 more answers
Determine the oh of a solution that is 0.220 m in hco3
ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

Explanation :

As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

As, 1 mole of HCO_3^- dissociates to give 1 mole of hydrogen ion (H^+)

Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

Now we have to calculate the hydroxide ion concentration.

As we know that:

[H^+][OH^-]=1\times 10^{-14}

0.200\times [OH^-]=1\times 10^{-14}

[OH^-]=5\times 10^{-14}

Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

6 0
4 years ago
I’LL MAKE YOU BRAINLIEST+ FREE POINTS
vladimir2022 [97]

Answer:

The solution's new volume is 1.68 L

Explanation:

Dilution is the procedure to prepare a less concentrated solution from a more concentrated one, and simply consists of adding more solvent. So, in a dilution the amount of solute does not vary, but the volume of the solvent varies.

In summary, a dilution is a lower concentration solution than the original.

The way to do the calculations in a dilution is through the expression:

Ci*Vi=Cf*Vf

where C and V are concentration and volume, respectively; and the i and f subscripts indicate initial and final respectively.

In this case, being:

  • Ci= 7 M
  • Vi= 0.60 L
  • Cf= 2.5 M
  • Vf=?

Replacing:

7 M*0.60 L= 2.5 M* Vf

Solving:

Vf=\frac{7 M*0.60 L}{2.5 M}

Vf= 1.68 L

<u><em>The solution's new volume is 1.68 L</em></u>

6 0
3 years ago
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