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ch4aika [34]
3 years ago
6

What is the best name for this molecule? Explain your naming process.

Chemistry
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

for compound CH3 it is named methyl or methyl, for compound CH3 -CH2-Ch2 C ||| since it is an alkyne for the triple bond that is why it is a group of carbons called propyne, on the other hand the last equation where CH3-CH-C is expressed, I think you meant CH3-CH-CH2 || with which this last serious propene since the double bond is what makes it an alkene.

Explanation:

The compound CH3-CH-C was considered poorly written since a carbon can always bind four hydrogens, so if the molecule is CH3 it is because it has 3 available bonds to bind with the hydrogens and one with an R (radical) If the molecule is CH2, it is because it is linked to two radicals on each side and it only has two available bonds for hydrogens or because it has a double bond, on the other hand, in the case that it is CH or it has a triple bond or is attached to three other radicals / carbons and only one bond is available for bonding with hydrogen-

It is important to understand that if a carbon in an organic chemical sequence is only expressed as C, it is because its four unions are occupied and cannot bind to hydrogens, thus being the opposite case of methane, which is CH4 where ALL ITS UNIONS ARE WITH HYDROGENS SINCE IT IS NOT JOINED TO ANY RADICAL.

Organic chemistry is difficult, I hope the equations you wrote are well expressed, otherwise if you have doubts you can consult me.

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When a strong acid is titrated with a strong base using phenolphthalein, the color changes suddenly at the end point. The color
larisa86 [58]

Answer:

Keto - enol tautomerism

Explanation:

Phenolphthalein is an organic molecule (formula: C20H14O4), which is used in to determine the final volume in an acid-base titration, this is, as the molecule changes from one to another color, depending on the Ph of the solution (in acids solution, the molecule remains colorless, while in basics solutions it remains pink)  :

The molecule of phenolphthalein is a week acid, which losses a proton (H+) when it´s in solution: the undissociated molecule is colorless, while the correspondent anion (without a H+) is pink. This may be simplified with the following reaction:

H₃In⁺ ⇄ H₂In (colorless) ⇄ In⁻² (pink) ⇄ In(OH) ⁻³

- When adding a base (for example, NaOH) to phenolphthalein (initially, a colorless solution), molecule losses one H⁺ and we obtain In⁻², which is pink

- When adding an acid, the original structured is recovered, so color turns from pink to colorless

This change color is not only explained with adding an acid or a base, but also with phenolphthalein structure, that leads to a keto-enol tautomerism: as molecule has 2 hydroxyl groups (- OH) and 1 carbonyl group (C = O), compounds with this structure have an equilibrium between both groups:

R1 = C H– OH ⇄  R1 – C = O

With this change, phenolphthalein structure changes and hence, color solution changes as well

4 0
3 years ago
What is the first step in nuclear fission?
lys-0071 [83]

Answer:

energy is released

Explanation:

8 0
4 years ago
What is a boundary between geologic units?
Airida [17]
The answer to this question is Contact
depending on the geological event that put into place, this will have a specific semantic value.
A contact usually represented by different kind of lines on the geological map and usually use to determine <span>where rocks come into contact across fault zones</span>
3 0
3 years ago
Read 2 more answers
He equation for the dissociation of pyridine is
sergeinik [125]

Answer:

10.10

Explanation:

Step 1: Write the basic dissociation reaction for pyridine

C₅H₅N(aq) + H₂O(l) ⇌ C₅H₅NH⁺(aq) + OH⁻(aq)      Kb = 1.9 × 10⁻⁹

Step 2: Calculate [OH⁻]

For a weak base, we will use the following expression.

[OH⁻] = √(Cb × Kb) = √(9.2 × 1.9 × 10⁻⁹) = 1.3 × 10⁻⁴ M

Step 3: Calculate pOH

We will use the definition of pOH.

pOH = -log [OH⁻] = -log 1.3 × 10⁻⁴ = 3.9

Step 4: Calculate pH

We will use the following expression.

pH = 14 - pOH = 14 - 3.9 = 10.10

3 0
3 years ago
A chemistry student needs 30,0 mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the stu
Marta_Voda [28]

Answer:

1.878g

Explanation:

Volume = 30.0ml

Density = 0.626gcm−3

Mass = ?

Be careful in this kind of questions to check for the units. In this case one has to remember 1 mL equal 1 cm³ so density = 0.626g/ml

The relationship between all three parameters is given by the equationn below;

Mass = Density * Volume

Mass = 0.626g/ml * 30 = 1.878g

8 0
3 years ago
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