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In-s [12.5K]
3 years ago
5

Which best explains the difference between a ball-and-stick model of a chemical compound and a space-filling model?

Chemistry
2 answers:
mr Goodwill [35]3 years ago
6 0

Answer:

The answer is C.

Explanation:

Nikolay [14]3 years ago
4 0
Scientists use models to show the characteristics of compounds. Of the different models,ball-and-stick model and space-filling model are commonly used but similar. Ball-and- stick model shows the bond between both atom and not the relative size of the atoms. Space-filling model shows the relative size of the atom and not the bond between the atoms. Both are 3-Dimensional and use color spheres within the model. 
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Molecules in 2 moles of carbon dioxide<br>​
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Answer:

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2 years ago
Volcanic activity during Earth’s formation is responsible for contributing a significant portion of CO2 and H2O to the atmospher
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6 0
2 years ago
Elemental iodine (I 2) is a solid at room temperature. What is the major attractive force that exists among different I 2 molecu
Ulleksa [173]

Explanation:

As I_{2} is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.

Hence, weak forces like london dispersion forces will be present between a molecule of I_{2}.

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

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7 0
3 years ago
How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmat
stira [4]

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

8 0
3 years ago
10. Identify the products in the combustion of methane.
Oksanka [162]

Answer:

a. CO2 and H20

Explanation:

Chemically, this combustion process consists of a reaction between methane and oxygen in the air. When this reaction takes place, the result is carbon dioxide (CO2), water (H2O), and a great deal of energy. The following reaction represents the combustion of methane:

CH4[g] + 2 O2[g] -> CO2[g] + 2 H2O[g] + energy

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8 0
2 years ago
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