1. U₂₃₈→α→Th₂₃₄(UX₁)
<span>2. Th₂₂₈→α→Ra₂₂₆(MsTh₁) </span>
<span>α = Alpha decay (release of He Nucleus) </span>
<span>The decay products are meso states that undergo further (β) decay</span>
Evaporation,condensation, and precipitation.
When there is heat released
Explanation:
It is known that the relation between heat energy, specific heat and change in temperature is as follows.
q =
where, q = heat released or absorbed
m = mass of substance
C = specific heat
= change in temperature
It is given that mass is 25.2 g and it is added to 150 ml container so total mass will be (25.2 g + 150 g) = 175.2 g,
is
,
is
, and specific heat of water is 4.184
.
Hence, putting the given values into the above formula as follows.
q =
=
= 
= -8430 J
As, 1 J = 0.001 kJ. Hence, -8430 J will also be equal to -8.43 kJ. The negative sign indicates that heat is being lost.
Thus, we can conclude that heat (kJ) was lost by the solution (surroundings) is 8.43 kJ.
Answer: Hope this helps
<h3>
Explanation: <u><em>
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