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Tamiku [17]
3 years ago
12

Your friend standing on a 45 foot balcony. He asks you to throw a baseball up to him. You throw a baseball with an initial upwar

d velocity of 50 ft./s. Assuming that you released the baseball 6 feet above the ground, did it reach your friend? Explain.
Mathematics
1 answer:
cricket20 [7]3 years ago
5 0

Vertical motion formula is h = -16t^2 +vt +s where v is initial velocity and s is starting height:

h = -16t^2 + 50t +6

Solving for t: -50/-32 = 1.5625 seconds to reach maximum height.

Now replace t  and solve for h ( maximum height)

h = -16(1.5625)^2 +50(1.5625) + 6

h = 45.0625

The value for h is greater than the height of the balcony, so yes the ball reached  the friend.

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\dfrac{V_s}{V_b}=(\dfrac{h_s}{h_b})^3\\\\\dfrac{V_s}{V_b}=(\dfrac{3}{5})^3\\\\\dfrac{V_s}{V_b}=0.216\\\\V_s=393\times 0.216\\\\V_s=84.8\\\\or\\\\V=85\ cm^3

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