What is a point slope equation of the line with slope -13 that goes through the point (5,7)

Mathematics

1 answer:

MaRussiya [10]2 years ago

8 0

Y=-13x+72 is the answer

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Solve r=4/3(p-q) for p

lesya [120]

Answer:

q+3/4r=p

Step-by-step explanation:

r=4/3(p-q)

Distribute the 4/3

r=4/3p-4/3q

Add 4/3q to each side

4/3q+r=4/3p

Multiply ALL variables by 3/4 (undoes the 4/3)

q+3/4r=p

<h2>Please mark me as brainliest</h2>

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2 years ago

6% of what number is 24

Flura [38]

Answer:

4 i think, sorry if incorrect

Step-by-step explanation:

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2 years ago

If angle 1 is 110°, what would the other angle measures have to be in order for m || n and

ra1l [238]

Answer:

Angle 2: 110 degrees, 1 and 2 would have to be the same for the lines to be parallel

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2 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$