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3 years ago

8

Carter's mom has ¼ of a pan of brownies leftover. If Carter and two of his friends share the leftover brownies equally, what fra

ction of the whole pan of brownies will each friend get?

1 answer:

antoniya [11.8K]3 years ago

3 0

Answer:

x/12

Step-by-step explanation:

1/4 of a pan of brownies leftover.

=1/4 of x

=1/4*x

=x/4

If Carter and two of his friends shares the leftover=3 people

Each friend will get

x/4÷3

=x/4×1/3

=x/12

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Step-by-step explanation:

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Suppose j varies jointly with g and v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.

vladimir2022 [97]

Answer:

$j=12$

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form $j = kgv$

where k is a constant

step 1

Find the value of k

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3 years ago

The flagpole in front of VHS 50 feet tall. The angle of elevation from the end of its shadow to the top of the flagpole is 46°.

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The length of the shadow is 48.28 feet.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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