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alukav5142 [94]
3 years ago
15

A houseplant is placed on a window sill that gets direct, bright sunlight

Chemistry
1 answer:
Molodets [167]3 years ago
7 0

Answer:

D. Phototropism

Explanation:

Plants, like every other living organism, responds to external stimulus. In this question, the stimulus is LIGHT from the sun entering through the window sill. The plant is responding positively to the light stimuli by growing towards the direction where the light is coming from. This exhibit is called PHOTOTROPISM.

Phototropism, comes from two words viz photo- meaning light and tropism- meaning movement. Hence, phototropism is the growth of an organism (plant in this case) in response to a light stimulus. The case described in this question is POSITIVE PHOTOTROPISM because the growth occurs towards the light source.

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A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the perce
STALIN [3.7K]

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂

The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

5 0
3 years ago
Using the clausius clapeyron equation determines the heat of vaporization from experimental measurements of vapor pressure. the
Temka [501]
The temperature of the pressure is 255
4 0
3 years ago
Estructura del Lewis del C 4+ ?
kow [346]

Answer:

electron is the donor

Explanation:

Based on Lewis Theory

5 0
3 years ago
Chemical Quantities "Molar Mass - 2 step" - Wksh #3 Directions: Use dimensional analysis to perform the following calculations.
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There are about 1.27  × 10^23 molecules present in 13.5 g of SO2.

<h3>What are molecules?</h3>

A molecule is the simplest part of a compound that have independent existence.

Number of moles of sulfur dioxide = 13.5 g/64 g/mol = 0.211 moles

If 1 mole of SO2 contains 6.02 × 10^23 molecules

0.211 moles of SO2 contains 0.211 moles × 6.02 × 10^23 molecules/1 mole

= 1.27  × 10^23 molecules

32 g of sulfur contains 6.02 × 10^23 atoms

x g of sulfur contains  2.23 x 10^23

x = 32 × 2.23 x 10^23 /6.02 × 10^23

x = 11.85 g

6.02 × 10^23 formula units has a mass of AgF = 127 g

x formula units has a mass of  = 42.15 g

x = 6.02 × 10^23 × 42.15/127

x = 2 × 10^23 formula units

6.02 × 10^23 formula units of Fe2O3 has a mass of 160 g

8.83 x 10^23 formula units of Fe2O3 has a mass of 8.83 x 10^23 x 160 g/6.02 × 10^23

x = 235 g

Learn more about formula unit: brainly.com/question/19293051

6 0
2 years ago
An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t
mel-nik [20]

Explanation:

The given data is as follows.

    coefficient of volume expansion of glycerin (\beta) = 5.1 \times 10^{-4} 1/^{o}C

     linear expansion coefficient of aluminum, (\alpha_{A}) = 23 \times 10^{-6} 1/^{o}C  

              Volume = 100 cm^{3}

The increase in volume of the cup will be calculated as follows.

                    \Delta V_{c} = V \times 3 \times \alpha \times \Delta T

                                 = 100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C

                                 = 75900 \times 10^{-6} cm^{3}

                                 = 0.0759 cm^{3}

Formula for increase in volume  of glycerine is as follows.

               \Delta V_{g} = V \times \beta_{g} \times \Delta T

                              = 100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C

                              = 0.5610 cm^{3}

Therefore, volume of glycerin spilled is calculated as follows.

                        \Delta V = \Delta V_{g} - \Delta V_{c}

                                     = (0.5610 - 0.0759) cm^{3}

                                     = 0.4851 cm^{3}

Thus, we can conclude that 0.4851 cm^{3} glycerin will spill out of the cup.

6 0
3 years ago
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