Answer:
B. It contains 15.0 grams of HNO₃ per 100 grams of solution.
Explanation:
- The percent of a solute in a solution is the mass of the solute (g) per 100 g of solution.
<em>So, an aqueous solution that is 15.0 percent HNO₃ by mass means that It contains 15.0 grams of HNO₃ per 100 grams of solution.</em>
1 molecule of glucose contains 6 atoms of C, 12 atoms of H , and 6 atoms of 0.1 mole of glucose contains 6 moles of C atoms , 12 moles of H atoms , and 6 moles of O atoms .
For 5.43 g/mL and 5.44 g/mL = 0.01 the least diff and most precise.
First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.
For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01
For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07
For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01
For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03
As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.
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Answer:
Mass of barium sulfate = 8.17 g
Explanation:
Given data:
Mass of sodium sulfate = 4.98 g
Mass of barium sulfate produced = ?
Solution:
Na₂SO₄ + Ba(NO₃)₂ → BaSO₄ + 2NaNO₃
Moles of sodium sulfate:
Number of moles = mass/molar mass
Number of moles =4.98 g / 142.04 g/mol
Number of moles = 0.035 mol
Now we will compare the moles pf sodium sulfate and with barium sulfate.
Na₂SO₄ : BaSO₄
1 : 1
0.035 : 0.035
Mass of barium sulfate:
Mass = number of moles × molar mass
Mass = 0.035 mol ×233.4 g/mol
Mass = 8.17 g
