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3 years ago

Where does most the candles light come from

Chemistry

2 answers:

Mashutka [201]3 years ago

7 0

Answer:

All the light a candle makes comes from a chemical reaction known as combustion in which the wax (made from carbon-based chemicals typically derived from petroleum) reacts with oxygen in the air to make a colorless gas called carbon dioxide. Water is also produced in the form of steam.

Explanation:

Hope this helps :)

cupoosta [38]3 years ago

4 0

Answer:

It comes from the chemical reaction of The wax and the gas because the wax is made up of carbon-based chemicals so the gas and carbon make the candle light =)

Explanation:

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A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in

In-s [12.5K]

Answer:

3.6667

Explanation:

For helium gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${5.6}\times {3.0}={P_2}\times {9.0} atm$

${P_2}=\frac {{5.6}\times {3.0}}{9.0} atm$

${P_1}=1.8667\ atm$

The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm

For Neon gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${3.6}\times {4.5}={P_2}\times {9.0} atm$

${P_2}=\frac {{3.6}\times {4.5}}{9.0} atm$

${P_1}=1.8\ atm$

The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm

Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.

6 0

3 years ago

In the reaction H2CO3 (aq) + 2NH3 (aq) ? 2NH4+ (aq) + CO32– (aq), which substance is reduced? A. H2CO3 B. NH3 C. NH4 D. CO3 E. N

Ede4ka [16]

Here h2co3 is reduced because it oxidizes nh3

4 0

3 years ago

As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,

Anettt [7]

Answer:

The molar solubility of nitrogen gas is $1.32\times 10^{-3}mol/L$ .

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{N_2}=K_H\times p_{liquid}$

where,

$K_H$ = Henry's constant = $6.26\times 10^{-4}mol/L.atm$

$p_{N_2}$ = partial pressure of nitrogen gas

Total air pressure = P = 2.71 atm

Percentage of nitrogen in air = 78.09%

Mole fraction of nitrogen , $\hi_{N_2}= 0.7809$

$p_{N_2}=P\times \chi_{N_2}=2.71 atm\times 0.7809$

Putting values in above equation, we get:

$C_{N_2}=6.26\times 10^{-4}mol/L.atm\times 2.71 atm\times 0.7809\\\\C_{N_2}=1.32\times 10^{-3}mol/L$

Hence, the molar solubility of nitrogen gas is $1.32\times 10^{-3}mol/L$ .

6 0

3 years ago

If a small amount of br2 is added to an aqueous solution of an unknown monosaccharide, the reddish-brown color of br2 will disap

Natalija [7]

Answer:
If a small amount of br2 is added to an aqueous solution of an unknown monosaccharide, the reddish-brown color of br2 will disappear if the monosaccharide is an Aldose.

Explanation:
This happens because the Aldose contains a carbonyl group called Alsedyde. Bromine being a oxidizing agent oxidizes the aldehyde functional group to Carboxylic Acid moiety. While this test is not positive in case of Ketonic Functional group.

4 0

3 years ago

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilo

Lynna [10]

Answer:

NA = 6.8 E-12 Kg H2(g) / hour

Explanation:

steady-state diffusion of A through non-diffuser B:

NA = (DAB/RTz)(p*A1 - p*A2)

∴ (A): H2(g)

∴ (B): Pd

∴ DAB = 1.7 E-8 m²/s

∴ p*A1 = 2.0 Kg H2 / m³ Pd

∴ p*A2 = 0.4 Kg H2 / m³ Pd

∴ z = 6 mm = 6 E-3 m

∴ T = 600°C ≅ 873 K

∴ R = 8.314 J/mol.K = 8.314 N.m/mol.K

⇒ NA = ((1.7 E-8)/(8.314)(873)(6 E-3))(2.0 - 0.4)

⇒ NA = 6.246 E-10 mol/s.m³

for A = 0.25 m²

⇒ volume (v) = A×z = (0.25)(6 E-3) = 1.5 E-3 m³

∴ Mw H2(g) = 2.016 g/mol

⇒ NA = (6.246 E-10 mol/s.m³)(1.5 E-3 m³)(2.016 g/mol)(Kg/1000 g)(3600 s/h)

⇒ NA = 6.8 E-12 Kg H2(g)/h

4 0

3 years ago

Where does most the candles light come from​

Where does most the candles light come from