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3 years ago

What is the mass of a sample of material that has a volume of 6260 and a density of 6980 g/cm

Chemistry

1 answer:

svet-max [94.6K]3 years ago

8 0

The mass of the sample is 436.9 t.

Mass = 6260 cm³× (6980 g/1 cm³) = 4.369 × 10⁸ g = 4.369 × 10⁵ kg =436.9 t

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If it takes 54ml of 0.1 m naoh to neutralize 125 ml of a hcl solution with unknown concentration, what is the concentration of t

dangina [55]

The balanced equation for the reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
number of NaOH moles reacted - 0.1 mol/L x 0.054 L = 0.0054 mol
number of HCl moles reacted = number of NaOH moles reacted
since the molar ratio of acid to base is 1:1
therefore number of HCl moles reacted - 0.0054 mol
the number of moles of HCl in 125 mL - 0.0054 mol
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4 years ago

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AlladinOne [14]

Explanation:

1). The given data is as follows.

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Hence, calculate the change in enthalpy of the reaction as follows.

$\Delta E_{rxn} = -C \times \Delta T$

= $-5.73 \times (38.13 - 25.87)^{o}C$

= -70.25 KJ

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= $\frac{1.55}{(6 \times 12 + 14 \times 1)}$

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Therefore, enthalpy of reaction in kJ/mol hexane is as follows.

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2). As we know that,

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= $\frac{1.55}{(7 \times 12 + 8 \times 1)}$

= 0.017 mol

$\Delta E_{rxn} = \E_{rxn} per mol \times \text{number of moles}$

= $-3.91 \times 10^{3} \times 0.017$

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-65.875 kJ = $-C \times (37.57 - 23.12)^{o}C$

C = 4.56 $kJ/^{o}C$

Hence, heat capacity of the bomb calorimeter is 4.56 $kJ/^{o}C$ .

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