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Scilla [17]
3 years ago
7

If you start with 10.0 grams of lithium hydroxide how many grams of lithium bromide will be produced

Chemistry
1 answer:
mamaluj [8]3 years ago
4 0
If you mean LiOH+HBr->LiBr+H2O
the answer is 0.4347mol LiBr and that equals (10/23)/80 gram LiBr

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a compound has an empirical formula of CH2 what is the molecular formula if it's molar mass is 252.5 grams/mol
Goryan [66]

Empirical formula is the simplest ratio of components making up the compound. the molecular formula is the actual ratio of components making up the compound.

the empirical formula is CH₂. We can find the mass of CH₂ one empirical unit and have to then find the number of empirical units in the molecular formula.

Mass of one empirical unit - CH₂ - 12 g/mol x 1 + 1 g/mol x 2 = 12 = 14 g

Molar mass of the compound is - 252 .5 g/mol

number of empirical units = molar mass / mass of empirical unit

                                           = \frac{252.5 g/mol}{14 g}

                                           = 18 units

Therefore molecular formula is - 18 times the empirical formula

molecular formula  - CH₂ x 18 = C₁₈H₃₆                                            

molecular formula is C₁₈H₃₆  

8 0
3 years ago
A student is asked to standardize a solution of barium hydroxide. He weighs out 0.978 g potassium hydrogen phthalate (KHC8H4O4,
Sav [38]

Answer:

(A) 0.129 M

(B) 0.237 M

Explanation:

(A) The reaction between potassium hydrogen phthalate and barium hydroxide is:

  • 2HA + Ba(OH)₂ → BaA₂ + 2H₂O

Where A⁻ is the respective anion of the monoprotic acid (KC₈H₄O₄⁻).

We <u>convert mass of phthalate to moles</u>, using its molar mass:

  • 0.978 g ÷ 156 g/mol = 9.27x10⁻³ mol = 9.27 mmol

Now we <u>convert mmol of HA to mmol of Ba(OH)₂</u>:

  • 9.27 mmol HA * \frac{1mmolBa(OH)_{2}}{2mmolHA} = 6.64 mmol Ba(OH)₂

Finally we calculate the molarity of the Ba(OH)₂ solution:

  • 6.64 mmol / 35.8 mL = 0.129 M

(B) The reaction between Ba(OH)₂ and HCl is:

  • 2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

So<u> the moles of HCl that reacted </u>are:

  • 17.1 mL * 0.129 M * \frac{2mmolHCl}{1mmolBa(OH)_2} = 4.41 mmol HCl

And the <u>molarity of the HCl solution is</u>:

  • 4.41 mmol / 18.6 mL = 0.237 M

3 0
3 years ago
If you wanted to protect water from freezing, which of the compounds below would accomplish this best. NaNO3, Mg(NO3)2, or Al(NO
Korvikt [17]
All of them are soluble salt.

First one dissociates into two ions.

The second one dissociates into 3 ions.

The third dissociate into 4 ions. therefore, Al(NO3)3
4 0
3 years ago
d) A short ton of coal holds about 2.24 x 107 J of energy and costs about $56.45 per short ton. How many Joules of energy in the
Feliz [49]

Answer:

396811.337 J

Explanation:

The cost of one short ton of coal = $56.45

The energy related to the short ton of coal = 2.24\times 10^{7}\ J

Thus, As according to the question,

$56.45 of coal have 2.24\times 10^{7}\ J of energy.

$1 of coal have \frac{2.24\times 10^{7}}{56.45}\ J of energy.

<u>The amount of energy = 396811.337 J</u>

4 0
3 years ago
The volume, in liters, occupied by 2.50 moles of N2 gas.<br><br><br> calculate at STP
kondaur [170]

Answer: The volume occupied by 2.50 moles of N_2 gas at STP is 56.0L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 2.50

R = gas constant =0.0821Latm/Kmol

T =temperature =273K  (at STP)

V=\frac{nRT}{P}

V=\frac{2.50mol\times 0.0821Latm/K mol\times 273K}{1atm}=56.0L

Thus the volume occupied by 2.50 moles of N_2 gas at STP is 56.0L

6 0
3 years ago
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