That is the wrong attiude!....dipwad.
Answer: vf= 364 m/s
Explanation: Use the formula for acceleration:
a= vf - vi / t
Derive for vf:
vf =( at )+ vi
= 5.4 m/s² ( 55s) + 67 m/s
= 364 m/s
the potential at the center of curvature of the arc = v = Q ∕ (4πε∘a) or 
ATQ,
We have density of charge,
λ = 
Where L is the rod's length, in this case the semicircle's length L = πr
Q is the charge on the rod
The potential created at the center by an differential element of charge is:
where k is the coulomb's constant
r is the distance from dQ to center of the circle
v = ∫ 
, Where a = radius, k = 1 / 4πε∘
v = or Q ∕ (4πε∘a)
To learn more about potential from the given link
brainly.com/question/25923373
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Because during a phase change nothing really happens. Before a phase change, energy and temperature will increase or decrease as well as after.
The right<span> at +20.0 </span>cm/s makes<span> an </span>elastic head<span>-on </span>collision<span> with a 10.0 </span>g object<span> that </span>makes<span> an</span>elastic head<span>-on </span>collision<span> with a 10.0 </span>g object<span> that is </span>initially<span> at </span>rest<span>.(b) Find the fraction of the </span>initial<span>kinetic energy transferred to the 10.0 </span>g object<span>.of small </span>mass<span> before and </span>after collision; V=velocity<span> of big </span>mass after collision<span>.</span>
