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BartSMP [9]
3 years ago
14

What do you notice about the three lines reflected from the convex mirror?

Physics
1 answer:
NemiM [27]3 years ago
5 0

Answer:

They are reflected back at the same angle they came in

Explanation:

When parallel light rays hit a convex mirror they reflect outwards and travel directly away from an imaginary focal point (F). Each individual ray is still reflecting at the same angle as it hits that small part of the surface.

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Calculate the weight of your energy car if it has a mass of 233.85 kg.
lianna [129]

Explanation:

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3 0
2 years ago
Please hellllooooppp
Lena [83]

Answer:

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Explanation:

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8 0
2 years ago
450 centimeters +500 millimeters = ___________ mm?
yawa3891 [41]

Answer:5000mm

Explanation:450cm=4500mm

4500mm+500mm=5000mm

7 0
3 years ago
A train pulls the boxcars. What are the vertical forces present? (1 point)
Greeley [361]

The vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

The forces exerted on an object can be resolved into <em>horizontal</em> and <em>vertical components.</em>

<em />

The horizontal components of the forces on an object being pulled include the following;

  • The frictional force on the object; which tends to reduce the motion,
  • force dragging the object forward
  • if the object is inclined to an angle, the horizontal component of the weight

This horizontal force is written as;

\Sigma F_x = 0\\\\F_x - F_k = ma

The vertical component of the force on the object include the following;

  • the weight of the object acting downwards
  • the pull of air on the object acting upwards

The vertical force on the object is written as;

\Sigma F_n = 0\\\\F_n - W = 0

Thus, the vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

Learn more here: brainly.com/question/2000189

5 0
2 years ago
A particle that has a charge of 7.4 μC moves with a velocity of magnitude 3 × 105 m/s along the +x axis. It experiences no magne
sweet [91]

Answer:

Explanation:

F = qvB

Where F equal to the magnetic force on the particle.

q = charge on the particle

v = velocity of the particle

B =Magnetic field

F = 0.520N

q = 7.4 μC = 7.4×10-⁶C

v = 3×10⁵m/s

B= ?

B = F/qv

B = 0.520/(7.4×10-⁶ ×3×10⁵)

B = 0.234T.

6 0
3 years ago
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