All categories

3 years ago

What do you notice about the three lines reflected from the convex mirror?

Physics

1 answer:

NemiM [27]3 years ago

5 0

Answer:

They are reflected back at the same angle they came in

Explanation:

When parallel light rays hit a convex mirror they reflect outwards and travel directly away from an imaginary focal point (F). Each individual ray is still reflecting at the same angle as it hits that small part of the surface.

You might be interested in

What label should mateo place in the marked cell? uses electrical energy provides electrical energy measures electric current co

ahrayia [7]

The product label which Mateo should place in the marked cell is that it: B. provides electrical energy.

<h3>What is a product label?</h3>

A product label can be defined as a paper-document with specific information about the chemical elements, nutrients, and other chemical compounds that are present in a product and its general use or function.

In this scenario, the product label which Mateo should place in the marked cell shown in the image attached below is that, this product was designed and developed to provide electrical energy, based on the electrical symbol for battery.

Read more on product label here: brainly.com/question/14446515

#SPJ4

4 0

2 years ago

A.to reduce<br> b.to dispose<br> c.to prevent<br> d.to help

kenny6666 [7]

Answer:

to prevent cuz now for my mind when you prevent it it will not happen to you or nothing happened to you

5 0

3 years ago

A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is

GarryVolchara [31]

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)$

so we have

$H = 1.47 m$

Part b)

Similarly when spring is compressed by 4 cm

then we have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)$

so we have

$H = 5.94 m$

8 0

4 years ago

Particles q1, q2, and q3 are in a straight line.

natima [27]

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

Learn more about force here:

brainly.com/question/25573309

#SPJ10

8 0

2 years ago

iv. An object is 14 cm in front of a convex mirror. The image is 5.8 cm behind the mirror. What is the focal length of the mirro

Dvinal [7]

Answer:

C. 9.9 cm

Explanation:

The location of the object, u = 14 cm

The location of the image, v = 5.8 cm

The focal length of the mirror, f = Required

The mirror formula for a convex mirror is given as follows;

$\dfrac{1}{u} -\dfrac{1}{v} = -\dfrac{1}{f}$

Therefore, we get;

$\dfrac{1}{14 \ cm} -\dfrac{1}{5.8 \ cm} =- \dfrac{41}{406 \ cm} = -\dfrac{1}{f}$

Therefore;

$f = \dfrac{406 \ cm}{41} \approx 9.9 \ cm$

The focal length of the mirror, f ≈ 9.9 cm

6 0

3 years ago