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hodyreva [135]
3 years ago
10

Identify the outer electron configurations for the (a) alkali metals, (b) alkaline earth metals, (c) halogens, (d) noble gases.

(a) Alkali metal: ns,1 ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (b) Alkaline earth metals: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (c) Halogens: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (d) Noble gases: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6.
Chemistry
1 answer:
ladessa [460]3 years ago
6 0

Answer:

Explanation:

Alkali metals   ------ outermost orbit containing one electron

ns²np¹

Alkaline metals -------- outermost orbit containing two electron

ns²np²

halogens --------------- outermost orbit containing seven electron

ns²np⁵

noble gas --------------- outermost orbit containing eight electron

ns²np⁶.

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Answer:

mass % = 28.4%

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Explanation:

Step 1: Data given

Volume of toluene = 50.0 mL = 0.05 L

Density toluene = 0.867 g/mL

Molar mass toluene = 92.14 g/mol

Volume of benzene = 125 mL = 0.125 L

Density benzene = 0.874 g/mL

Molar mass benzene = 78.11 g/mol

Step 2: Calculate masses

Mass = density * volume

Mass toluene = 50.0 mL * 0.867 g/mL = 43.35 g

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Step 3: Calculate number of moles

Moles = mass / molar mass

Moles toluene = 43.35 grams /92.14 g/mol = 0.470 5 moles

Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

Step 4: Calculate molarity of toluene

Molarity = moles / volume

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Step 5: Calculate mass % of toluene

Mass % = (43.35 grams / (43.35 + 109.25) )*100 % = 28.4 %

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Step 7: Molality of toluene

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Molality of toluene = 0.4705 moles / (0.04335 + 0.10925)

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Answer:

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Time - second (s)

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Explanation:

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