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hodyreva [135]
3 years ago
10

Identify the outer electron configurations for the (a) alkali metals, (b) alkaline earth metals, (c) halogens, (d) noble gases.

(a) Alkali metal: ns,1 ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (b) Alkaline earth metals: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (c) Halogens: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (d) Noble gases: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6.
Chemistry
1 answer:
ladessa [460]3 years ago
6 0

Answer:

Explanation:

Alkali metals   ------ outermost orbit containing one electron

ns²np¹

Alkaline metals -------- outermost orbit containing two electron

ns²np²

halogens --------------- outermost orbit containing seven electron

ns²np⁵

noble gas --------------- outermost orbit containing eight electron

ns²np⁶.

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zhuklara [117]

Answer: n= 3, l= 0 , m= 0 and s=[/tex]\frac{-1}{2}[/tex]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic quantum number :  It describes the orientation of the orbital. It is represented as 'm'. The value of m ranges from -l to +l.

Spin quantum number:  It describes the spin of the electron. It is represented as 's'. The value of s can be +1/2 or -1/2

F^{2-}:11: 1s^22s^22p^63s^1

F^{3-}:12:1s^22s^22p^63s^2

Thus electron enters 3s orbital , thus n= 3, l= 0 , m= 0 and s=[/tex]\frac{-1}{2}[/tex]

4 0
3 years ago
11. A 4.175 gram sample of a certain hydrate of copper (II) sulfate, CuSO,• xH,O, is heated until all
Wewaii [24]

The  formula of the hydrate = CuSO₄• 3H₂O

<h3>Further explanation</h3>

Given

4.175 grams sample CuSO₄• xH₂O

3.120 grams anhydrous compound CuSO₄

Required

The formula

Solution

mass of H₂O driven off :

= 4.175 - 3.12

= 1.055 g

MW CuSO₄ = 159.5 g/mol

MW H₂O = 18 g/mol

mol ratio of CuSO₄ : H₂O :

= 3.12/159.5 : 1.055/18

= 0.01956 : 0.05861

= 1 : 3

3 0
3 years ago
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Ann [662]
I believe the answer is 16
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3 years ago
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san4es73 [151]

Answer: ABC

Explanation:

4 0
3 years ago
Read 2 more answers
A block is found to have volume of 35.3 cm3. It’s mass is 31.7g. Calculate the density of the block
11111nata11111 [884]

Answer:

<h2>1.11 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{35.3}{31.7}  \\  = 1.113564

We have the final answer as

<h3>1.11 g/mL</h3>

Hope this helps you

6 0
3 years ago
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