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Gala2k [10]
3 years ago
14

If n II p and p ⊥ m , then??? helpppppp

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0

Answer:

I think is p/L

Step-by-step explanation:

8_murik_8 [283]3 years ago
6 0

Answer:

The answer is last option N perpendicular to M . It is justified but others are not

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Can some help me pls
marissa [1.9K]

Answer:

1. 0=0

2. x= -3

3. 14=0

Step-by-step explanation:

I tried I'm sorry if it's wrong

5 0
3 years ago
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of
Tema [17]

Answer:

Small box weighs 13.75 kg & large box weighs 15.75 kg

Step-by-step explanation:

We can write 2 simultaneous equation and solve for weight of each box.

<em>Let weight of large box be l and small box be s.</em>

<em />

"<u>3 large boxes and  5 small boxes has a total weight of  116 kilograms</u>":

3l+5s=116

and

"<u>9 large boxes and  7 small boxes has a total weight of  238 kilograms</u>":

9l+7s=238

<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>

<em>3l+5s=116\\3l=116-5s\\l=\frac{116-5s}{3}</em>

<em>now,</em>

<em>9l+7s=238\\9(\frac{116-5s}{3})+7s=238\\3(116-5s)+7s=238\\348-15s+7s=238\\348-238=15s-7s\\110=8s\\s=\frac{110}{8}=13.75</em>

<em />

<em>now we plug in 13.75 into s into equation of l to find s:</em>

<em>l=\frac{116-5s}{3}\\l=\frac{116-5(13.75)}{3}\\l=15.75</em>

5 0
3 years ago
Lines c and d are parallel. The equation of line c is y=−3x−5. What is the equation of line d?
Natali [406]

Answer: y = -3x - 5

Step-by-step explanation: since the two lines are parallel, it implies that

m1 = m2. From the equation given,

m1 = -3 , m2 = -3

Substantial for m2 in y = mx + c

We now have

y = -3x - 5 since the new line is not passing through any coordinate.

7 0
3 years ago
(3xsecond powery) (-4xythird power)
Alla [95]
Https://www.cymath.com/answer.php?q=(3x%5E2)(-4xy%5E3)

-12x^3y^3
6 0
3 years ago
Read 2 more answers
solve for x. I'm confused on whether we are suppose to expand or condense it, and on what log property do we use.
topjm [15]
\bf log_4(x-2)+log_4(5)=log_4(70)\\\\&#10;-----------------------------\\\\&#10;log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)\\\\&#10;-----------------------------\\\\&#10;log_4[5(x-2)]=log_4(70)\impliedby \textit{take out the } log_4 \textit{ from both sides}&#10;\\\\\\&#10;5(x-2)=70\implies x-2=\cfrac{70}{5}\implies x-2=14\implies x=16
8 0
3 years ago
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