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VikaD [51]
3 years ago
5

Which equation is correct?

Mathematics
2 answers:
Yuri [45]3 years ago
4 0

Answer:

The expression that represents  is

Step-by-step explanation:

The trigonometric equation given to us is

We take the cosine inverse of both sides to obtain,

Recall that, the composition of a function of x and its inverse produces x.

That is  or

Similarly,

This implies that,

The correct answer is C.

Step-by-step explanation:

rodikova [14]3 years ago
3 0

Answer: arccsc(x)=arcsin(1/x)

Step-by-step explanation:

Edg2020

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Help Me on this math equation​
igomit [66]

Answer:

uhhhh what grade level is dis?

Step-by-step explanation:

4 0
2 years ago
A particle decays at a rate of 0.45% annually. assume and initial amount of 300 mg. (
raketka [301]
The increase is an exponential increase in a multiplier
100%+0.45%=100.45% and as decimal 1.0045

Final Value = Initial Value × multiplier^{number of years}
Final value = 300(1.0045)^{60}
Final value = 393 mg (to the nearest whole number)

Half life = 0.5 years
Final value = 300(1.0045)^{0.5}=301 mg
6 0
4 years ago
HURRY QUICK!! Apply the distributive property to create an equivalent expression. 1/2 ( 6e - 3f - 3/4 )
tensa zangetsu [6.8K]

Answer:

1 2/6      3 3/4

Step-by-step explanation:

7 0
4 years ago
The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
3 years ago
23,674=38<br> ---------------<br> b
Maru [420]
Is there a picture or is it just that
8 0
3 years ago
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