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Step2247 [10]
3 years ago
6

If now Kate is three times as old as Jan, and 6 years ago she was six times as old as he was, how old are they now?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

<h2>Jan is 10 years old.</h2><h2>Kate is 30 years old.</h2>

Step-by-step explanation:

To solve this problem, we need to find a system of equations.

<h3>Now: Kate is three times as old as Jan.</h3>

This statement can be expressed as K=3J, beacuse "three times" indicates a product.

<h3>6 years ago: She was six times as old as he was.</h3>

This statement can be expressed as K-6=6(J-6), notice that we had to subtract 6 units, representing 6 years in the past.

Let's replace the first equation into the second one

3J-6=6(J-6)\\3J-6=6J-36\\-6+36=6J-3J\\3J=30\\J=\frac{30}{3}\\ J=10

Therefore, Jan is 10 years old.

Then, K=3J \implies K=3(10)=30

Therefore, Kate is 30 years old.

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115% is the same as 1.15
some number = x

115% of some number is 120
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\frac{1.15*x}{1.15} = \frac{120}{1.15}
x = 104.3478
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Hope this helps! :)
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Is the point (3, 4) a solution to the equation 3y = 2x +6 ? Explain why using evidence from your work
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Step-by-step explanation:

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3 years ago
Which expressions are equivalent to the one below? Check all that apply. <br><br> 9^x
AveGali [126]

Answer:

A) 3^{x}*3^{x}

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Step-by-step explanation:

Given the exponential expression, 9^{x}:

A)  3^{x}*3^{x} is equivalent to 9^{x} due to the Product Rule of exponents:  a^{m} a^{n} = a^{m + n}.  

  • 3^{x}*3^{x} = 3^{x+x} = 3^{2x}

Next, apply the Power-to-Power Rule of exponents:  a^{mn} = (a^{m} )^{n}.  

  • 3^{x}*3^{x} = 3^{x+x} = 3^{2x} = (3^{2})^{x}  = 9^{x}

B)   3^{2x}  is equivalent to 9^{x} due to the Power-to-Power Rule of exponents:  a^{mn} = (a^{m} )^{n}.  

  • 3^{2x} = (3^{2})^{x} = (9)^{x} = 9^{x}.    

C)  (3 * 3)^{x}  is equivalent to 9^{x} due to the Product-to-Power Rule of exponents:  (ab)^{m} = a^{m} b^{m}.  

  • (3 * 3)^{x} = (9)^{x}  = 9^{x}  
5 0
3 years ago
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