Is the point (3, 4) a solution to the equation 3y = 2x +6 ? Explain why using evidence from your work

Mathematics

1 answer:

irinina [24]3 years ago

7 0

Answer:

Yes

Step-by-step explanation:

When graphing it you can see that (3, 4) is clearly a solution. The proper equation using slope intercept form is y= 2/3x + 2.

You might be interested in

Quadratic function of Y=x2-2x-3

Svetach [21]

Ok! So, given a quadratic function, y = ax2 + bx + c, when "a" is positive, the parabola opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, y = x2, where "a" is 1.

Hope this helps.

6 0

3 years ago

What is the inverse of the function g(x)= -3(x + 6)? g-1(x) =

Elanso [62]

Here’s the answer. See pictures.

3 0

2 years ago

Two mathematical questions attached below.

BartSMP [9]

Answer:

See below

Step-by-step explanation:

$9.( {m}^{3} {n}^{5} )^{ \frac{1}{4} } \\ = m^{\frac{3}{4}}n^{\frac{5}{4}}\\ \\ 10. \sqrt[5]{ \sqrt[4]{x} } \\ = \sqrt[5]{ {x}^{ \frac{1}{4} } } \\ = {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} } \\ = {x}^{ \frac{1}{4} \times \frac{1}{5} } \\ = {x}^{ \frac{1}{20} } \\ \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } } \\ = \sqrt[5]{ {a}^{ \frac{2}{3} } } \\ = {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} } \\ = {a}^{ \frac{2}{3} \times \frac{1}{5} } \\ = {a}^{ \frac{2}{15} }$