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Rom4ik [11]
3 years ago
6

A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. How tall is the l

edge? A. 313.6 meters B. 78.4 meters C. 39.2 meters D. 1,254.4 meters
Physics
2 answers:
Alex_Xolod [135]3 years ago
7 0
The right answer for the question that is being asked and shown above is that: "D. 1,254.4 meters." A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. The ledge has the height of <span>D. 1,254.4 meters</span>
In-s [12.5K]3 years ago
7 0

By the way, on the Penn Foster test, C. 1,254.4 meters is incorrect.

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Three-point charges are arranged on a line. Charge q3 = +5.00nC and is at the origin. Charge q2 = -3.00 nC and is at x = 5.00 cm
Anon25 [30]

Answer:

Explanation:

Given

Charge q_3=+5\ nC is placed at origin

Charge q_2=-3\ nC is placed at x=5\ cm

Charge q_1 is Placed at x=2.5\ cm

charge q_1 must be positive so as to balance the force on charge q_3

Force on q_3 due to q_1 is

F_{31}=\frac{kq_1q_3}{r^2}

here r=2.5\ cm

F_{31}=\frac{kq_1q_3}{(2.5)^2}

Force on q_3 due to q_2 is

F_{32}=\frac{kq_3q_2}{r^2}

here r=5\ cm

F_{32}=\frac{kq_3q_2}{(5)^2}

F_{31}=F_{32}

\frac{kq_1q_3}{(2.5)^2}=\frac{kq_3q_2}{(5)^2}

q_1=q_2(\frac{2.5}{5})^2

q_1=3\times (\frac{2.5}{5})^2

q_1=3\times \frac{1}{4}

q_1=0.75\ nC

                                                                   

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3 What is the displacement of a satellite when it makes a complete round along its circular path?​
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