3. One cubic metre is equal to

Mayan kings and many school sports teams are named for the puma, cougar, or mountain lion felis concolor, the best jumper among

denis23 [38]

To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2°)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.

4 0

2 years ago

While Robert was helping his father in the garden, he pushed a shovel into the ground to dig a hole in the dirt. He picked up a

makvit [3.9K]

Work done is given by the change in kinetic energy of an object

The kinetic energy of the shovel, the shrub, and in Robert's movement were changed, therefore, work is done in the given processes,

Reason:

Work is done when the total energy of object is affected by the application of force on the object over a distance

Therefore;

In option A, pushing the shovel into ground (to dig out the dirt) the requires the application of a force (push) over a distance, (into and out of the ground) therefore work is done

In option B, picking the shrub up gives it gravitational potential energy, therefore, work is done

In option C, carrying the shrub to the hole does visible work

In option D, holding the shrub while lowering it into the hole does work by preventing the shrub from falling randomly

Therefore, work is done in the given processes

Learn more about work-energy theorem here:

brainly.com/question/10063455

7 0

2 years ago

11. a 0.12-kg, 50-cm-long uniform bar has a small 0.055-kg mass glued to its left end and a small 0.11-kg mass glued to the othe

Eduardwww [97]

The left end should the fulcrum be placed is 29.8 cm.

What is fulcrum?
The lever's pivot point is known as a fulcrum. You probably first came across a fulcrum on the playground, directly beneath the see-saw. Any general prop as well as support was referred to as a fulcrum in the 17th century. Thanks to physics class, it now has more scientific connotations. However, the term "fulcrum" is still frequently used to refer to something that is central to an event or activity, as in "the fulcrum of a debate." Who is the father who arranges everyone's playdates? He serves as the focal point of the playground social group.

counter clockwise moments = clockwise moments
(0.055 kg * x) + (0.120*(x-25)) = 0.110 kg * (50-x)
0.055x + 0.12x - 3 = 5.5 - 0.11x
x = 29.8 cm

To learn more about fulcrum
brainly.com/question/28320996
#SPJ4

7 0

5 months ago

An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I

oksano4ka [1.4K]

Answer:

The deviation in path is $4.39 \times 10^{-3}$

Explanation:

Given:

Velocity $v = 1 \times 10^{6}$ $\frac{m}{s}$

Electric field $E = 500$ $\frac{V}{m}$

Distance $x = 1 \times 10^{-2}$ m

Mass of electron $m = 9.1 \times 10^{-31}$ kg

Charge of electron $q = 1.6 \times 10^{-19}$ C

Time taken to travel distance,

$t = \frac{x}{v}$

$t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }$

$t = 10^{-8}$ sec

Acceleration is given by,

$F = qE$

$ma = qE$

$a = \frac{qE}{m}$

$a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }$

$a = 8.77 \times 10^{13}$ $\frac{m}{s^{2} }$

For finding the distance, we use kinematics equations.

$y = vt + \frac{1}{2} at^{2}$

Where $v = 0$ because here initial velocity zero

$y = \frac{1}{2} at^{2}$

$y = \frac{1}{2} \times 8.77 \times 10^{13 } \times (10^{-2} )^{2}$

$y = 4.39 \times 10^{-3}$ m

Therefore, the deviation in path is $4.39 \times 10^{-3}$

6 0

2 years ago

What is the kinetic energy of a 145 g baseball moving at 42 m/s?

klio [65]

Answer:
Kinetic energy = 127.89 Joules

Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
m is the mass = 145 g = 0.145 kg
v is the velocity = 42 m/sec

Substitute in the above equation to get the kinetic energy as follows:
KE = (0.5)(0.145)(42)^2
Kinetic energy = 127.89 Joules

Hope this helps :)

8 0

2 years ago

3. One cubic metre is equal to​

3. One cubic metre is equal to