Hello, I need help please with this question if anyone could help me!

1 answer:

5 0

For some reason my computer says their is a picture but the picture doesn't go with the equation and the equation isn't matching everything else you said, sorryyy :(

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Which is the best first step and explanation for solving this system of equations? 3x+4y=12 3x=2y-8

Greeley [361]

Answer:

Since it is a simultaneous equation,

Using elimination method, Multiply equation 1 by the co efficient of x in equation 2 and multiply equation 2 by the co efficient of x in equation 1.

Step-by-step explanation:

For further explanation , Please contact me through the comment section.

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3 years ago

Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative

SVETLANKA909090 [29]

I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.

Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.

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3 years ago

Read 2 more answers

Find the distance from P to l.

ki77a [65]

$Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\$

$Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}$