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3 years ago

How do electric field lines indicate the strength of the field?

Physics

2 answers:

Paha777 [63]3 years ago

6 0

I am almost sure it it (c)

KiRa [710]3 years ago

3 0

<h2>Answer:</h2>

The correct answer is the option B which is by how close the lines are.

<h3>Explanation:</h3>

Electric field of lines are a type of pattern used to describe the direction and the strength of the electric field.
These are lines which always projects from Positive ions to negative ions.
Then strength of electric field is shown by the closeness of lines.
Where these lines are close to each other it means strength of electric field is high and vice versa.
These lines show that electric field is a vector property.

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What are Newton’s 3 laws

Vladimir79 [104]

Newton's First Law of Motion:

I. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.

Newton's Second Law of Motion:

II. The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma. Acceleration and force are vectors (as indicated by their symbols being displayed in slant bold font); in this law the direction of the force vector is the same as the direction of the acceleration vector.

Newton's Third Law of Motion:

III. For every action there is an equal and opposite reaction.

3 0

3 years ago

Read 2 more answers

In this section of a circuit, a current of 2.0 A flows across R1. What is the current across R2? Let R1 = 4.0 ohm, R2 = 8.0 ohm,

Liono4ka [1.6K]

Answer:

I=1A

Explanation:

In parallel combination voltage is same

In R1

V=IR

V=2×4

V=8V

In R2

V=IR

I=V/R

I=8/8

I=1A

3 0

4 years ago

Suppose the first coil of wire illustrated in the simulation is wound around the iron core 7 times. Suppose the second coil is w

SVETLANKA909090 [29]

Answer:

Emf induced in the coli will be equal to 26 volt

Explanation:

We have given number of turns N = 13

It is given that magnetic flux changes from 2.1 Weber to 2.7 Weber in 0.3 sec

Change in flux $d\Phi =2.7-2.1=0.6Weber$

Change in time dt = 0.3 sec

We have to find the induced emf

Induced emf is equal to $e=N\frac{d\Phi }{dt}=13\times \frac{0.6}{0.3}=26volt$

So emf induced in the coil will be equal to 6 volt

5 0

3 years ago

Read 2 more answers

answers Collision derivation problem. If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 12/75, the in

Natasha2012 [34]

Answer:

4.8967m

Explanation:

Given the following data;

M = 0.2kg

∆p = 0.58kgm/s

S(i) = 2.25m

Ratio h/w = 12/75

Firstly, we use conservation of momentum to find the velocity

Therefore, ∆p = MV

0.58kgm/s = 0.2V

V = 0.58/2

V = 2.9m/s

Then, we can use the conservation of energy to solve for maximum height the car can go

E(i) = E(f)

1/2mV² = mgh

Mass cancels out

1/2V² = gh

h = 1/2V²/g = V²/2g

h = (2.9)²/2(9.8)

h = 8.41/19.6 = 0.429m

Since we have gotten the heigh, the next thing is to solve for actual slant of the ramp and initial displacement using similar triangles.

h/w = 0.429/x

X = 0.429×75/12

X = 2.6815

Therefore, by Pythagoreans rule

S(ramp) = √2.68125²+0.429²

S(ramp) = 2.64671

Finally, S(t) = S(ramp) + S(i)

= 2.64671+2.25

= 4.8967m

3 0

3 years ago

An element with 1 valence electron has a charge of

ziro4ka [17]

<span>An element with 1 valence electron has a charge of -1, because there is an extra negatively charged electron attached to the ion.</span>

6 0

4 years ago