How do electric field lines indicate the strength of the field?

Physics

2 answers:

Paha777 [63]3 years ago

6 0

I am almost sure it it (c)

KiRa [710]3 years ago

3 0

<h2>Answer:</h2>

The correct answer is the option B which is by how close the lines are.

<h3>Explanation:</h3>

Electric field of lines are a type of pattern used to describe the direction and the strength of the electric field.
These are lines which always projects from Positive ions to negative ions.
Then strength of electric field is shown by the closeness of lines.
Where these lines are close to each other it means strength of electric field is high and vice versa.
These lines show that electric field is a vector property.

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A small metal ball is given a negative charge, then brought near to end a of the rod (figure 1). What happens to end a of the ro

erma4kov [3.2K]

What happens to end a of the rod when the ball approaches it closely this first time is; It is strongly attracted.

<h3>Electrostatics</h3>

I have attached the image of the rod.

We are told that the ball is much closer to the end of the rod than the length of the rod. Thus, if we point down the rod several times, the distance of approach will experience no electric field and as such the charge on end point A of the rod must be comparable in magnitude to the charge on the ball.

This means that their fields will cancel.

Finally, we can conclude that when a charge is brought close to a conductor, the opposite charges will all navigate to the point that is closest to the charge and as a result, a strong attraction will be created.

This also applies to a strong conducting rod and therefore it is strongly attracted.

Read more about Electrostatics at; brainly.com/question/18108470

7 0

2 years ago

Please help !!

nikitadnepr [17]

If the speed is constant, the acceleration a must be zero. Since force F = m•a, the total force must be zero.
In a 1D case, work W is the product of force F and distance d: W = F • d.
Since there is no more information given about friction or air resistance, I have to assume you are looking for the work done by the total force, wich is also zero.

3 0

3 years ago

A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?

Strike441 [17]

p = 36 kgm/s

v = 4m/s

we know that,

p = mv

so,

$m = \frac{p}{v}$