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Lynna [10]
3 years ago
14

A baseball with a mass of 300 g has a kinetic energy of 304 J. Calculate the speed of the baseball

Physics
2 answers:
KatRina [158]3 years ago
5 0

Answer:

v = 45.02 m/s

Explanation:

scZoUnD [109]3 years ago
4 0

The formula for kinetic energy is equal to 1/2mv^2, where "m" is the mass of the object (in kilograms) and "v" is equal to the velocity of the object (in meters per second). To calculate the speed, simply plug in the values and solve.

KE = 0.5mv^2

304 J = 0.5(0.3 kg)v^2         -mass converted from grams to kilograms

v = 45.02 m/s

The baseball is travelling about 45.02 meters per second.

Hope this helps!

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Which sound wave-object interaction is used by animals in echolocation?
tekilochka [14]
The answer is reflection
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3 years ago
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If the speed of light in a substance is 2.26 x 10^8 m/s, what is the index of refraction of that substance?
vladimir1956 [14]

Answer:

1.33

Explanation:

speed of light in vacuum, c = 3 x 10^8 m/s

speed of light in medium, v = 2.26 x 10^8 m/s

The refractive index of the medium is given by

μ = speed of light in vacuum / speed of light in medium

μ = (3 x 10^8) / (2.26 x 10^8)

μ = 1.33

4 0
2 years ago
A physics book is thrown horizontally at a velocity of 5.0 m/s from the top of a cliff 78.4 m high. How long does the book take
xenn [34]

The book's vertical position in the air is

y=78.4\,\mathrm m-\dfrac12gt^2

where g=9.80\,\frac{\mathrm m}{\mathrm s}. It reaches the ground when y=0, at a time t such that

0=78.4\,\mathrm m-\dfrac12gt^2\implies t=4.00\,\mathrm s

So it takes the book 4 seconds to reach the bottom. The given initial velocity is irrelevant since it only has a horizontal component; vertically, the book is starting from rest.

3 0
3 years ago
A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafl
aalyn [17]

Answer:

The answer is "82.2 torr"

Explanation:

moles of Xe:

= \frac{0.06}{131.293} \\\\ =0.00045699313 \ \mol

moles of F_2:

= \frac{0.0274}{38} \\\\= 0.00072105263\ \  mol

moles of produced XeF_2:

= 0.00024

moles of left Xe:

= 0.00021

Calculate the Pressure:

= \frac{(0.08206\times 0.00024 \times 293)}{(.1)}   + \frac{(0.08206\times  0.00021 \times  293)}{(.1)} \\\\= 0.10819611 \ \ atm \\\\ = 0.10819611 \times  760 \\\\ = 82.2 \ \ torr

5 0
2 years ago
HELP PLEASE!!!<br><br> a= ?<br><br> v=<br><br> r=
ratelena [41]

Answer:

a=\frac{v^2}{r}

v=\sqrt{a*r}

r=\frac{v^2}{a}

Explanation:

This is the formula for centripetal acceleration in terms of the tangential velocity (v) and the radius of the circular motion (r).  The expression for the acceleration is already given, so simply type it as shown:

a=\frac{v^2}{r}

For the velocity (v) multiply by "r" both sides and then use the square root to solve for v:

a*r=v^2\\v=\sqrt{a*r}

For the radius multiply both sides by r and then divide both sides by the acceleration (a) in order to isolate r completely:

a*r=v^2\\r=\frac{v^2}{a}

4 0
3 years ago
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