Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
Conjecture : 2xy / ( x + y ) ≤ √xy
Step-by-step explanation:
Harmonic mean of x and y = 2xy/( x + y )
<u>Formulate a conjecture about their relative sizes </u>
we will achieve this by computing harmonic and geometric means
Geometric mean = √xy
harmonic mean = 2xy/( x + y )
Conjecture : 2xy / ( x + y ) ≤ √xy
attached below is the proof
Answer:24
xexponet
3
−
5
Step-by-step explanation:
The decimal equivalent of 1/4 is 0.25.
The apporoximate length of the RP is 6.1 units, the correct option is B.
<h3>
What is Pythagoras theorem?</h3>
The Pythagoras theorem states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of the other two sides of the right-angled triangle.
Given
QR is the tangent to circle P at point Q.
QP = 3 units and QR = 5,.3 units
The length of the RP is given by;

Hence, the apporoximate length of the RP is 6.1 units.
To know more about Pythagoras theorem click the link given below.
brainly.com/question/11526258