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2 years ago

A 5.00 Ω, a 10.0 Ω, and a 15.0 Ω resistor are connected in

Physics

1 answer:

Bad White [126]2 years ago

7 0

Answer: Option C) 3A

Explanation:

Given that,

Voltage = 90.0 Volts

Current I = ?

R1 = 5.0Ω

R2 = 10.0Ω

R3 = 15.0Ω

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2 + R3

Rtotal = 5.0Ω + 10.0Ω + 15.0Ω = 30.0Ω

Then, apply the formula for ohms law

Voltage = Current x resistance

V = I x Rtotal

90.0V = I x 30.0Ω

I = 90.0V / 30.0Ω

I = 3 Amps (Amps is the unit of current)

Thus, the current in the circuit is 3 Amps

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<h3>Question:</h3>

How to find g (acceleration due to gravity)

<h3>Solution:</h3>

We know,

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Putting these values of G, M and R in the above formula, we get

$g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2}$

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$9.8m/s ^{2}$

Hope it helps.

Do comment if you have any query.

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2 years ago

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EleoNora [17]

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force = 2500kg x 2m/s^2
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2 years ago

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2 years ago

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Murrr4er [49]

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Paraphin [41]

Answer:

v = 3200 m/s

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3 years ago