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3 years ago

A 5.00 Ω, a 10.0 Ω, and a 15.0 Ω resistor are connected in

Physics

1 answer:

Bad White [126]3 years ago

7 0

Answer: Option C) 3A

Explanation:

Given that,

Voltage = 90.0 Volts

Current I = ?

R1 = 5.0Ω

R2 = 10.0Ω

R3 = 15.0Ω

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2 + R3

Rtotal = 5.0Ω + 10.0Ω + 15.0Ω = 30.0Ω

Then, apply the formula for ohms law

Voltage = Current x resistance

V = I x Rtotal

90.0V = I x 30.0Ω

I = 90.0V / 30.0Ω

I = 3 Amps (Amps is the unit of current)

Thus, the current in the circuit is 3 Amps

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3 years ago

A carbon rod with a radius of 1.9 mm is used to make a resistor. What length of the carbon rod should be used to make a 3.7 Ω re

vladimir2022 [97]

Answer:

Length = 2.32 m

Explanation:

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First, let us find the area of the circular rod.

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$R=\rho( \frac{L}{A})$

Express this in terms of 'L'. This gives,

$\rho\times L=R\times A\\\\L=\frac{R\times A}{\rho}$

Now, plug in the given values and solve for length 'L'. This gives,

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3 years ago

Pls heplp 70 points!!!!!

Rasek [7]

Answer

the answer is d for sure

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3 years ago