Question

If there is no real number solution to the quadratic equation x^2+2x+c=0 what is a possible value of c?

Answer 1

Answer:

3

Step-by-step explanation:

Given

x² + 2x + c = 0 ← in standard form

with a = 1, b = 2 and c = c

If there are no real solutions then the discriminant

b² - 4ac < 0, that is

2² - (4 × 1 × c ) < 0

4 - 4c < 0 ( subtract 4 from both sides )

- 4c < - 4

Divide both sides by - 4, reversing the sign as a consequence

c > 1

Hence a possible value of c is 3

Answer 2

Answer:

The possible value of 'x' is: 3.

Step-by-step explanation:

A polynomial has no real solutions when the discriminat is less than zero. Given the following polynomial: $ax^{2} +bx+c = 0$ the discriminant is given by: $Discriminant = b^{2}-4ac$

In this case, a=1, b=2. By substituting those values:

$Discriminant = 2^{2}-4(1)c$ ⇒ $Discriminant = 4-4c$

Given that the discriminant should be less tha zero, then 'c' must be greater than one.

In this case, the only possible value of 'x' is: 3.