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3 years ago

Two spheres have radii 6 and 15. Find the ratios of the areas and the volumes.

Mathematics

1 answer:

lina2011 [118]3 years ago

4 0

Answer:

1st sphere has r1 = 6

=> Surface area S1 = 4 x pi x r1^2 = 4 x pi x 6^2 = 144pi

=> Volume V1 = (4/3) x pi x r1^3 = (4/3) x pi x 6^3 =288pi

2nd sphere has r1 = 15

=> Surface area S1 = 4 x pi x r1^2 = 4 x pi x 15^2 = 900pi

=> Volume V1 = (4/3) x pi x r1^3 = (4/3) x pi x 15^3 =4500pi

=> S1/S2 = 144pi/900pi = 0.16

=> V1/V2 = 288pi/4500pi = 0.064

Hope this helps!

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Find the length of the third side. If necessary, write in simplest radical form.

Mazyrski [523]

Answer:

$\boxed {\boxed {\sf 8}}$

Step-by-step explanation:

This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

$a^2+b^2=c^2$

Where a and b are the legs of the triangle and c is the hypotenuse.

In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

$a= 7 \\b= \sqrt{15}$

Substitute these values into the formula.

$(7)^2+(\sqrt{15})^2=c^2$

Solve the exponents.

(7)²= 7*7=49

$49+ (\sqrt{15})^2=c^2$

(√15)²=√15*√15=15

$49+15=c^2$

Add.

$64=c^2$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt{64}=\sqrt{c^2} \\\sqrt{64}= c\\8=c$