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Anni [7]
2 years ago
7

A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car’s acceleration?

Chemistry
2 answers:
faltersainse [42]2 years ago
6 0
Answer is 2m/s sq because V-u /t us acceleration 40-10/15=2
Firlakuza [10]2 years ago
6 0

Answer : The car’s acceleration is, 2m/s^2

Solution :

Acceleration : It is defined as the change in the velocity of an object with respect to the time.

Formula used :

a=\frac{v_{final}-v_{initial}}{t}

where,

a = acceleration of car = ?

v_{final} = final velocity of car = 40 m/s

v_{initial} = initial velocity of car = 10 m/s

t = time taken = 15 s

Now put all the given values in this formula, we get the acceleration of car.

a=\frac{40m/s-10m/s}{15s}=2m/s^2

Therefore, the acceleration of car is, 2m/s^2

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Option B

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What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?
yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃  +  3C  →  4Fe  +  3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

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