Volume= Mass/ Density= 20/184
= 0.108 cubic cm
Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.
Explanation :
(a) At constant volume condition the entropy change of the gas is:

We know that,
The relation between the
for an ideal gas are :

As we are given :



Now we have to calculate the entropy change of the gas.


(b) As we know that, the work done for isochoric (constant volume) is equal to zero. 
(C) Heat during the process will be,

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.
The specific heat is the amount of heat per unit mass required to raise the temperature to 1 degree Celsius. (This is from google)
Answer:
2Au₂S₃ + 6H₂ → 4Au + 6H₂S
Explanation:
Balancing:
2Au₂S₃ + 6H₂ → 4Au + 6H₂S
Answer:

Explanation:
The formula for the amount of heat absorbed by a substance is
q = mCΔT
Thus, the three factors are the
- mass
- specific heat capacity
- temperature change
The only factor that is on your list is

The shape of the substance has no effect, nor do its melting and boiling points.