1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anni [7]
3 years ago
7

A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car’s acceleration?

Chemistry
2 answers:
faltersainse [42]3 years ago
6 0
Answer is 2m/s sq because V-u /t us acceleration 40-10/15=2
Firlakuza [10]3 years ago
6 0

Answer : The car’s acceleration is, 2m/s^2

Solution :

Acceleration : It is defined as the change in the velocity of an object with respect to the time.

Formula used :

a=\frac{v_{final}-v_{initial}}{t}

where,

a = acceleration of car = ?

v_{final} = final velocity of car = 40 m/s

v_{initial} = initial velocity of car = 10 m/s

t = time taken = 15 s

Now put all the given values in this formula, we get the acceleration of car.

a=\frac{40m/s-10m/s}{15s}=2m/s^2

Therefore, the acceleration of car is, 2m/s^2

You might be interested in
Find the volume of an object that has a mass of 20g and density of 184 glcm
expeople1 [14]
Volume= Mass/ Density= 20/184
= 0.108 cubic cm
8 0
3 years ago
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
The specific heat of a given substance
Lelechka [254]
The specific heat is the amount of heat per unit mass required to raise the temperature to 1 degree Celsius. (This is from google)
7 0
3 years ago
___ Au₂S₃ + ___ H₂ → ___ Au + ___ H₂S
Natalija [7]

Answer:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

Explanation:

Balancing:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

6 0
3 years ago
Which of the following factors affects the amount of heat absorbed by a substance?
Ilia_Sergeevich [38]

Answer:

\boxed{\text{Specific heat capacity of the substance}}

Explanation:

The formula for the amount of heat absorbed by a substance is

q = mCΔT

Thus, the three factors are the

  • mass
  • specific heat capacity
  • temperature change

The only factor that is on your list is

\boxed{\textbf{Specific heat capacity of the substance}}

The shape of the substance has no effect, nor do its melting and boiling points.

3 0
3 years ago
Other questions:
  • When carbon undergoes sp2 hybridization it forms
    12·1 answer
  • Please help me with my chemistry
    14·2 answers
  • A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
    9·1 answer
  • 12. Identify the following as a chemical or physical change:
    8·1 answer
  • A student uses 0.0821 L• atm/mol • K as the value of the gas constant. What is most likely true about the variables in the ideal
    15·2 answers
  • What will happen if there is no gravitational force​
    5·1 answer
  • All objects have mass<br> O True<br> O False
    15·1 answer
  • The table below shows the number of sub-atomic particles in an atom of magnesium.
    5·1 answer
  • A balloon is filled with 100.0 Lair at 1.300 atm pressure. what pressure is needed to change the volume to 25.00 L
    12·1 answer
  • (need help asap)
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!