The concentration of the reactants and products remain constant. Because the rates of the forward and reverse reaction are equal there is no net change to the amount of reactants or products produced.May 19, 2011
953.6 g of iron (III) oxide (Fe₂O₃)
Explanation:
We have the following chemical reaction:
2 Fe₂O₃ (s) + 3 C (s) → 4 Fe (s) + 3 CO₂ (g)
We calculate the number of moles of CO₂ by using the following formula:
pressure × volume = number of moles × gas constant × temperature
number of moles = (pressure × volume) / (gas constant × temperature)
number of moles of CO₂ = (2.1 × 100) / (0.082 × 300)
number of moles of CO₂ = 8.54 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 mole of Fe₂O₃ produces 3 mole of CO₂
then X moles of Fe₂O₃ produces 8.54 mole of CO₂
X = (2 × 8.54) / 3 = 5.69 moles of Fe₂O₃
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of Fe₂O₃ = 5.69 × 160 = 953.6 g
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number of moles
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Answer:
Option C. Triple the number of moles
Explanation:
From the ideal gas equation:
PV = nRT
Where:
P is the pressure
V is the volume
n is the number of mole
R is the gas constant
T is the absolute temperature.
Making V the subject of the above equation, we have:
PV = nRT
Divide both side by P
V = nRT / P
Thus, we can say that the volume (V) is directly proportional to both the number of mole (n) and absolute temperature (T) and inversely proportional to the pressure (P). This implies that and increase in either the number of mole, the absolute temperature and a decrease in the presence will cause the volume to increase.
Thus, the correct option is option C triple the number of moles. This can further be seen as illustrated below:
Initial volume (V1) = 12 L
Initial mole (n1) = 0.5 mole
Final mole (n2) = triple the initial mole = 3 × 0.5 = 1.5 mole
Final volume (V2) =?
From:
V = nRT / P, keeping T and P constant, we have:
V1/n1 = V2/n2
12/0.5 = V2/1.5
24 = V2/1.5
Cross multiply
V2 = 24 × 1.5
V2 = 36 L.
Thus Option C gives the correct answer to the question.