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evablogger [386]

3 years ago

10

Please help me and hurry

2 answers:

n200080 [17]3 years ago

8 0

Answer:

a) Median = 91

b) mode = 91

c)Mean 84.2

Step-by-step explanation:

a) Median is the middle term. So, 6th term

Median = 91

b) Mode is the score which occurs more number of times

91 occurs 3 times

Mode = 91

c) Mean= sum of all data's/Number of data's

= 85 + 91 + 48 +98 + 99 /5

= 421/5

Mean = 84.2

Dmitry [639]3 years ago

5 0

Answer:

median: 90

mode: 91

mean: 84.2 or round it to 84

Step-by-step explanation:

Let me know if this helps! have a great day! :)

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On Friday 237 people attended film festival.there r more 446 people who attended on Saturday than Friday .liza says that a total

pentagon [3]

Liza is wrong because...

Friday = 237
Saturday = 237 + 446
Both days = 920

4 0

3 years ago

If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]? a)29.5 b)30 c)43 d)120

avanturin [10]

$\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
f(x)= x^3-x \qquad 
\begin{cases}
x_1=1\\
x_2=5
\end{cases}\implies \cfrac{f(5)-f(1)}{5-1}
\\\\\\
\cfrac{[5^3-5]~-~[1^3-1]}{4}\implies \cfrac{125-5~~-~~0}{4}\implies \cfrac{120}{4}\implies 30$

7 0

3 years ago

For each sequence find the first 4 terms and the 10th term

jolli1 [7]

Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:

a) 1 (1st term) + 5 = 6

2 (2nd term) + 5 = 7

3 (3rd term) + 5 = 8

4 (4th term) + 5 = 9

10 (10th term) + 5 = 15

And so on for b (not going to keep writing the term, I’m sure you get that by now.

b) 2(1) - 1 = (2x1) - 1 = 1

2(2) - 1 = (2x2) - 1 = 3

2(3) - 1 = (2x3) - 1 = 5

2(4) - 1 = (2x4) - 1 = 7

2(10) - 1 = (2x10) - 1 = 19

Hope this helps :)

4 0

3 years ago

Antonius the chef wants to cook several batches of lasagna and spaghetti for his restaurant. He plans to use at least 4.54.5 kil

yaroslaw [1]

Answer: No he does not meet both of his expectation by cooking 10 batches of spaghetti and 4 batches of lasagna.

Step-by-step explanation:

Since here S represents the number of batches of spaghetti and L represents the total number of lasagna.

And, the chef planed to use at least 4.5 kilograms of pasta and more than 6.3 liters of sauce to cook spaghetti and lasagna.

Which is shown by the below inequality,

$0.3S+0.65L \geq 4.5$ ----------(1)

And, $0.25S+0.8L >6.3$ --------(2)

By putting S = 10 and L = 4 in the inequality (1),

$0.3\times 10+0.65\times 4 \geq 4.5$

⇒ $5.6\geq 4.5$ (true)

Thus, for the values S = 10 and L = 4 the inequality (1) is followed.

Again By putting S = 10 and L = 4 in the inequality (2),

$0.25\times 10+0.8\times 4 >6.3$

⇒ $5.7>6.3$ ( false)

But, for the values S = 10 and L = 4 the inequality (2) is not followed.

Therefore, Antonius does not meet both of his expectations by cooking 10 batches of spaghetti and 4 batches of lasagna.

4 0

3 years ago

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Montano1993 [528]

The equation is option number c because someth = smth

4 0

3 years ago

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