Answer:
32.5 m/s
Explanation:
The total momentum must be conserved before and after the collision:
where
m_c = 300 kg is the mass of the car
m_t = 600 kg is the mass of the truck
u_c = 60 m/s is the initial velocity of the car
u_t = 10 m/s is the initial velocity of the truck
v_c = 15 m/s is the final velocity of the car
v_f is the final velocity of the truck
Solving for v_f, we find:
Answer:
v
f=90km/h=25m/s
v_{_{i}}=0v
i=0
t=10\;\mathrm{s}t=10s
m=1000\;\mathrm{kg}m=1000kg
The coefficient of friction between the sled and the snow is 0.119.
To find the answer, we need to know about the friction.
<h3>How to find the coefficient of friction between the sled and the snow?</h3>
- Whenever a body moves over the surface of another body, a force come into play, which acts parallel to the surface of contact and oppose the relative motion. This opposing force is called friction.
- To solve the problem, we have to draw the free body diagram of the given system.
- We have given with the following values,
Here, acceleration will be equal to zero, because the velocity is given as constant.
- Thus, from the diagram, we can write the balancing equations as follows,
- Substituting N in f and f in the equation of ma, then we get,
- Substituting values, we get the coefficient of friction as,
Thus, we can conclude that, the coefficient of friction between the sled and the snow is 0.119.
Learn more about the friction here:
brainly.com/question/28107059
#SPJ1
Answer:
statements <em><u>2, 3, 4, and 7</u></em> are true
Explanation:
Here average speed for given motion is defined as ratio of total distance covered by total time
so here we can say
here total distance can be calculated by formula
distance = speed * time
here given that its average speed is v = 2.05 m/s
for first half let the time is "t " seconds and the speed for that is 2.01 m/s
and for next half time will be same and it is "t " seconds again
so by plug in all data in above equation we have
so its speed for next half must be 2.09 m/s